Java Regex not working as desired [closed]

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I created this regex, but somehow it only detects the first part of the regex not the last part. I would like to know what is going on?

Here's the code:

String m = -2√3254i/18.5
String regex = "-?\\d+(\\.\\d*)?\\√\\d+(\\.\\d*)?i\\/\\d+(\\.\\d*)?"

I have tried many different ways, such as:

-?\\d+(\\.\\d*)?\\√\\d+(\\.\\d*)?i+\\/+\\d+(\\.\\d*)?
-?\\d+(\\.\\d*)?\\√\\d+(\\.\\d*)?i/\\d+(\\.\\d*)?
-?\\d+(\\.\\d*)?\\√\\d+(\\.\\d*)?i\\(\\/\\d+(\\.\\d*))?

none of them work.

the output is always

-2√3254

Any suggestions,

thank you

what did you mean by but somehow it only detects the first part of the regex not the last part ? — Youcef LAIDANI
– Youcef LAIDANI, Commented May 7, 2017 at 20:27
I expect to get the whole string. Well it only gives me back -2√3254 not the entire string, which is what I expect. @YCF_L — i_o
– i_o, Commented May 7, 2017 at 20:29
did you mean String m = "-2√3254i/18.5"; String regex = "-?\\d+(\\.\\d*)?\\√\\d+(\\.\\d*)?i+\\/+\\d+(\\.\\d*)?"; Pattern pattern = Pattern.compile(regex); Matcher matcher = pattern.matcher(m); if (matcher.find()) { System.out.println(matcher.group()); } ? — Youcef LAIDANI
– Youcef LAIDANI, Commented May 7, 2017 at 20:45

Youcef LAIDANI · Accepted Answer · 2017-05-07 21:27:01Z

1

Okay so my regex is actually composed of many regexes:

String regex = "a regex | another regex | -?\\d+(\\.\\d*)?\\√\\d+(\\.\\d*)?\\i" 
              + "|another regex | -?\\d+(\\.\\d*)?\\√\\d+(\\.\\d*)?i\\/\\d+ (\\.\\d*)?

The problem happens between both regexes shown. The first symbolical regex is picked up by the matcher first, but I really intended for the second symbolical regex to pick up my String m = "-2√32454i/18.5"

It seems the matcher exits matching when one of the boolean conditions is met. All I had to do was rearrange the order of my regexes which make up my regex.

edited May 7, 2017 at 21:27

Youcef LAIDANI

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answered May 7, 2017 at 21:18

i_o

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