Error message: Object not found! on calling PHP script in AJAX

Question

I have created a very basic page that retrieves all contacts from my contact MySQL table using AJAX:

index.php

html xmlns="http://www.w3.org/1999/xhtml">
  <head>
    <title>mycontacts.</title>
    <script type="text/javascript" src="JavaScripts/PrintContacts.js"></script>
  </head>

  <body>
    <div class="main-wrapper">
      <div id="main-content">

        <script type="text/javascript">
          printContacts();
        </script>

        <div id="contacts">
        </div>

      </div>
    </div>
  </body>
</html>

PrintContacts.js

var xmlHttp;

function printContacts() {
  xmlHttp = new XMLHttpRequest();
  var url = "PHP/getAllContacts.php";

  // Workaround for page caching
  url = url + "&sid=" + Math.round(Math.random() * 1000000000);
  // Commenting the line above removes my issue but I do need this for caching!!!

  // Manage XmlHttpObject state change
  xmlHttp.onreadystatechange = stateChanged;

  xmlHttp.open("POST", url, true);
  xmlHttp.send(null);
}

function stateChanged() {
  // Check if the XmlHttp request is complete
  if (xmlHttp.readyState == 4) {
    // Set the XmlHttp response in the div contacts
    document.getElementById("contacts").innerHTML = xmlHttp.responseText;
  }   
}

getAllContacts.php

<?php
$dbconnection = mysql_connect("localhost", "root", "");
mysql_select_db("mycontacts", $dbconnection);

$command = "SELECT * FROM contact";
$result = mysql_query($command);

echo "<table border='1'>";

// Table headers
echo "<tr><th>Name</th></tr>";

// Print all contacts
while($row = mysql_fetch_array($result)) {
  echo "<tr>";
  echo "<td>" . $row['DisplayName'] . "</td>";
  echo "</tr>";
}

echo "</table>";

mysql_close($dbconnection);
?>

Opening the getAllContacts.php directly returns the appropriate table with the data, however, opening index.php, results in an error:

Object not found!

The requested URL was not found on this server. The link on the referring page seems to be wrong or outdated. Please inform the author of that page about the error.
If you think this is a server error, please contact the webmaster.

Error 404

localhost
12/08/2010 2:47:27 PM
Apache/2.2.14 (Win32) DAV/2 mod_ssl/2.2.14 OpenSSL/0.9.8l mod_autoindex_color PHP/5.3.1 mod_apreq2-20090110/2.7.1 mod_perl/2.0.4 Perl/v5.10.1

I found out that adding &SID= is the root of the issue. This is happening in the PrintContacts.js file. Removing that loads the page appropriately. But I DO need that in order to workaround the caching. Do you know how to resolve this?

Thanks for all the help.

Solution

When adding SID to the url (for caching purposes), it should be appended with "?sid=" instead of "&sid=". Changing this resolves the issue; it was a typo after all!

function printContacts() {
  xmlHttp = new XMLHttpRequest();
  var url = "PHP/getAllContacts.php";

  // Workaround for page caching
  url = url + "&sid=" + Math.round(Math.random() * 1000000000);
  ...

mikesir87 · Accepted Answer · 2010-12-08 15:39:40Z

1

When using AJAX, the url should be linked based on the browser's current location, not the location of the javascript file.

Change the url in printContacts() to just "PHP/getAllContacts.php".

EDIT: Ok... I figured it out! In the PrintContacts.js, you need to change this line

url = url + "&sid=" + Math.round(Math.random() * 1000000000);

to this...

url = url + "?sid=" + Math.round(Math.random() * 1000000000);

Note the question mark in there. Having the & made it look for a file named getAllContacts.php&192837, not a file named getAllContacts.php.

edited Dec 8, 2010 at 15:39

answered Dec 8, 2010 at 14:37

mikesir87

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3 Comments

Boris Over a year ago

Thanks for the heads-up. I did make a change, but the error is the same. Any other suggestions? Thanks.

mikesir87 Over a year ago

Another thing to try is using the Firebug extension for Firefox, and looking at the Net tab to see what's going on. It'll tell you the paths it's using, what the return code is, etc. Might help you out.

Boris Over a year ago

OK, I found out that adding &SID=<random_number> is the root of the issue. Removing that loads the page appropriately. But I DO need that in order to workaround the caching. Do you know how to resolve this? Thanks.

Shakti Singh · Accepted Answer · 2010-12-08 14:36:23Z

0

I am going to suggest only one thing

can you please use the full url instead

 var url = "http://www.blahblah.com/PHP/getAllContacts.php";

answered Dec 8, 2010 at 14:36

Shakti Singh

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1 Comment

Boris Over a year ago

I've tried that, same error. It makes no sense.. Could it be that I need to configure something in XAMPP (apache)?

Jasper De Bruijn · Accepted Answer · 2010-12-08 14:36:39Z

0

My guess is that your error lies here:

var url = "../PHP/getAllContacts.php";

Replace the url with either the absolute url, or something relative to the domain instead of relative to the JS file.

answered Dec 8, 2010 at 14:36

Jasper De Bruijn

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1 Comment

Boris Over a year ago

Thanks for the reply. Actually, I tried using absolute url, as recommended by @Shakti Singh below, but the error is the same. Any other suggestions?

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