Selenium Webdriver : How to upload file using his relative path (javascript)

Question

I'm using selenium webdriver with node.js (javascript ) under chrome.

In some test , i have to upload a file using his relative path (my file to upload is in the same directory as the test file)

var fileInput = driver.findElement(webdriver.By.xpath('//*[@id="j_idt69:j_idt70_input"]'));
fileInput.sendKeys('./file.xml');

Strangely my test fails and i catch this error :

My error handler... WebDriverError: unknown error: path is not absolute:

In fact am using a relative path because my test is intented to be used in differents locations (VMs , jenkins , pc..). and the absolute path isn't usefull for me.

Suggestions ??

how about finding out an absolute path dynamically and using it? — Vladimir M
– Vladimir M, Commented May 10, 2017 at 9:07
'./file.xml' mewans your file is in project directory, is it so? — Kushal Bhalaik
– Kushal Bhalaik, Commented May 10, 2017 at 9:08

firasKoubaa · Accepted Answer · 2017-05-10 10:02:51Z

5

i have solved it this way :

detecting the absolute path dynamically and concat it with my file name :

To detect the current directory path using this node command : process.cwd()

the resulting path is : var path = process.cwd()+'/file.xml';

uploading action : fileInput.sendKeys(path);

edited May 10, 2017 at 10:02

answered May 10, 2017 at 9:51

firasKoubaa

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Comments

Eknath · Accepted Answer · 2017-05-10 09:41:27Z

1

sendKeys not support relative path as a argument.

Use System.getProperty("user.dir") to get current working directory path.

 String path=System.getProperty("user.dir")
 fileInput.sendKeys(path+"\\file.xml");

answered May 10, 2017 at 9:41

Eknath

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