typescript anonymous nested types

Question

given the following type:

type Foo = {
  a: {
    b: number
    c: string
  }
  d: number
}

is there a way to retrieve the anonymous nested types? I was thinking something like TypeOf<Foo, 'a'> should return the type made of b and c and TypeOf<Foo, 'd'> should be an alias to number. I made up the syntax, but I wanted to know if a similar concept exists

Giacomo Tagliabue · Accepted Answer · 2017-05-12 14:52:12Z

1

turns out you can do this by doing Foo['a']. Great!

answered May 12, 2017 at 14:52

Giacomo Tagliabue

1,7993 gold badges15 silver badges32 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

Ruan Mendes Over a year ago

If you're going to reuse the inner type, you should make a real type for clarity

Giacomo Tagliabue Over a year ago

that's not always possible. In my case this type comes from a code generator, so I am stuck with that. I still don't know how to handle complex cases like if a is optional, then Foo['a']['b'] will throw, do you know how to address this?

Ruan Mendes Over a year ago

No, I had not even heard of this solution you found

Collectives™ on Stack Overflow

typescript anonymous nested types

1 Answer 1

3 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

3 Comments

Your Answer

Sign up or log in

Post as a guest

Related