Ruby grep regex pattern and store it in an array

Question

Is the highlighted section allowed in ruby ?

......
......
text = File.read(file_name)
....
....
row = text.grep(/#{Regexp.escape(line)}/g) { |log| log.split.first } 
puts "From: #{row}"
.......
......

('line' is the variable substitution holds string values like -rr0\hu)

I know I can use the below method to read and search a pattern in files but I have to read multiple files and check if string is present (may be in multiple lines) and get the first word of matched string's line(s).

File.open('abc.txt').grep(/rr0\hu/) { |line| line.split.first }

How can I do this in Ruby?

letitworknow · Accepted Answer · 2017-05-13 11:36:12Z

1

Use the "match" string method and loop through each line of the file

fh = File.open('/path/to/file.txt', 'r') # If there are multiple files just loop through them.
fh.each_line do |line|
     if line.match(/REGEX/) then # "match" will find the regex in each line.
          puts line.split(" ")[0] # "split" will only print the first word of the matching string line
     end
end

edited May 13, 2017 at 11:36

answered May 13, 2017 at 11:30

letitworknow

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1 Comment

voltas Over a year ago

thank you for the match method. I made some modifications to cater my requirement. thanks again.

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