regex. Find multiple occurrence of pattern

Question

I have the following string

my_string = "this data is F56 F23 and G87"

And I would like to use regex to return the following output

['F56 F23', 'G87']

So basically, I'm interested in returning all the parts of the string that start with either F or G and are followed by two numbers. In addition, if there are multiple consecutive occurrences I would like regex to group them together.

I approached the problem with python and with this code

import re
re.findall(r'\b(F\d{2}|G\d{2})\b', my_string)

I was able to get all the occurrences

['F56', 'F23', 'G87']

But I would like to have the first two groups together since they are consecutive occurrences. Any ideas of how I can achieve that?

yep, I mean that there's just one white space between them

Brian
– Brian

2017-05-15 15:44:03 +00:00
Commented May 15, 2017 at 15:44 — Brian
– Brian, Commented May 15, 2017 at 15:44

anubhava · Accepted Answer · 2017-05-15 15:44:19Z

4

You can use this regex:

\b[FG]\d{2}(?:\s+[FG]\d{2})*\b

Non-capturing group (?:\s+[FG]\d{2})* will find zero or more of the following space separated F/G substrings.

Code:

>>> my_string = "this data is F56 F23 and G87"
>>> re.findall(r'\b[FG]\d{2}(?:\s+[FG]\d{2})*\b', my_string)
['F56 F23', 'G87']

answered May 15, 2017 at 15:44

anubhava

790k67 gold badges603 silver badges671 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

willeM_ Van Onsem · Accepted Answer · 2017-05-15 15:44:51Z

3

So basically, I'm interested in returning all the parts of the string that start with either F or G and are followed by two numbers. In addition, if there are multiple consecutive occurrences I would like regex to group them together.

You can do this with:

\b(?:[FG]\d{2})(?:\s+[FG]\d{2})*\b

in case it is separated by at least one spacing character. If that is not a requirement, you can do this with:

\b(?:[FG]\d{2})(?:\s*[FG]\d{2})*\b

Both the first and second regex generate:

>>> re.findall(r'\b(?:[FG]\d{2})(?:\s+[FG]\d{2})*\b',my_string)
['F56 F23', 'G87']
>>> re.findall(r'\b(?:[FG]\d{2})(?:\s*[FG]\d{2})*\b',my_string)
['F56 F23', 'G87']

answered May 15, 2017 at 15:44

willeM_ Van Onsem

482k33 gold badges483 silver badges624 bronze badges

Comments

am2 · Accepted Answer · 2017-05-15 16:02:27Z

0

print map(lambda x : x[0].strip(), re.findall(r'((\b(F\d{2}|G\d{2})\b\s*)+)', my_string))

change your regex to r'((\b(F\d{2}|G\d{2})\b\s*)+)' (brackets around, /s* to find all, that are connected by whitespaces, a + after the last bracket to find more than one occurance (greedy)

now you have a list of lists, of which you need every 0th Argument. You can use map and lambda for this. To kill last blanks I used strip()

answered May 15, 2017 at 16:02

am2

3718 silver badges23 bronze badges

Collectives™ on Stack Overflow

regex. Find multiple occurrence of pattern

3 Answers 3

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related