How to pass a string as an argument in python without "namespace"

Question

How do you pass a string as an argument in python without the output containing "Namespace".

Here is my code:

import argparse
parser = argparse.ArgumentParser()
parser.add_argument("person", help="person to test",type=str)
person = str(parser.parse_args())
print "The person's name is " + person

Here is the command I am running:

python test.py bob

This is my output:

The person's name is Namespace(person='bob')

I could probably do some fancy splitting, but I'm sure I'm just leveraging the argparse incorrectly(I'm new to python) if anyone can please tell me how to properly pass a string like this I would greatly apreciate it.

Maybe go through the first little bit of the argparse tutorial — nbryans
– nbryans, Commented May 16, 2017 at 20:34
There is an awesome library for this called click, check it out click.pocoo.org/5 — olofom
– olofom, Commented May 16, 2017 at 20:35

FamousJameous · Accepted Answer · 2017-05-16 20:34:24Z

11

The namespace is a container for the results of argument parsing. You can access the individual argument values by looking them up in the namespace:

import argparse
parser = argparse.ArgumentParser()
parser.add_argument("person", help="person to test",type=str)
args = parser.parse_args()
print "The person's name is " + args.person

The docs have some great examples that show how to use argparse.

answered May 16, 2017 at 20:34

FamousJameous

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1 Comment

Vincent Morris Over a year ago

Thanks! This worked like a charm, and your explanation makes perfect sense

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