36

I have problem when trying to parse with minimum value to map in Android.

There some sample JSON format with more information ex:

[{id:"1", name:"sql"},{id:"2",name:"android"},{id:"3",name:"mvc"}]

This that example most common to use and easy to use just use getString("id") or getValue("name").

But how do I parse to map using this JSON format with just only string and value minimum format to java map collection using looping. And because the string json will always different one with another. ex:

{"1":"sql", "2":"android", "3":"mvc"}

Thank

0

2 Answers 2

90

You need to get a list of all the keys, loop over them and add them to your map as shown in the example below:

    String s = "{menu:{\"1\":\"sql\", \"2\":\"android\", \"3\":\"mvc\"}}";
    JSONObject jObject  = new JSONObject(s);
    JSONObject  menu = jObject.getJSONObject("menu");

    Map<String,String> map = new HashMap<String,String>();
    Iterator iter = menu.keys();
    while(iter.hasNext()){
        String key = (String)iter.next();
        String value = menu.getString(key);
        map.put(key,value);
    }
Sign up to request clarification or add additional context in comments.

2 Comments

What's the import for JSONObject?
@8bitjunkie, It's org.json:json
11

My pseudocode example will be as follows:

JSONArray jsonArray = "[{id:\"1\", name:\"sql\"},{id:\"2\",name:\"android\"},{id:\"3\",name:\"mvc\"}]";
JSON newJson = new JSON();

for (each json in jsonArray) {
    String id = json.get("id");
    String name = json.get("name");

    newJson.put(id, name);
}

return newJson;

2 Comments

Probably because they're asking about a json object not json array.
@PixMach the String the OP provided is a JSON array. It starts with a [ and ends with a ].

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.