Match by regular expression to string replace by JavaScript

Question

My string is like

5blog5sett5ings5[5slider5][5][5ima5ge5]

I like to match any digit into second brackets from end by regular expression.

For this case, my target digit is 5 into [5].

I like to select where before pattern like
5blog5sett5ings5[5slider5][ and after pattern like ][5ima5ge5]

I will use it for JavaScript string replace. Text can be different but the before and after patterns are like that. For better understanding see the image.

I tried something like

(?<=.+[.+?][)\d(?=][.+?])

but did not work.

What have you tried so far? Which programing language are you using? — Pedro Lobito
– Pedro Lobito, Commented May 21, 2017 at 11:51
Why do you think regular expressions are the answer here, instead of string replacements? — DigiFriend
– DigiFriend, Commented May 21, 2017 at 11:52
I tried something like (?<=.+[.+?][)\d(?=][.+?]) but did not work. — webHasan
– webHasan, Commented May 21, 2017 at 11:56
If you just want to match the digit, try \d+(?=]\[[^\]]*]$) — bobble bubble
– bobble bubble, Commented May 21, 2017 at 12:00

bobble bubble · Accepted Answer · 2017-05-21 12:03:01Z

1

I think you could just use a lookahead to check if there ] and one more [ ] ahead until end.

\d+(?=]\[[^\]]*]$)

See demo at regex101

(be aware that lookbehind you tried is not available in js regex)

answered May 21, 2017 at 12:03

bobble bubble

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Pedro Lobito · Accepted Answer · 2017-05-21 12:02:36Z

1

I guess you can use:

\[(\d+)\][^\]]+]$

Regex Demo & Explanation

var myString = "5blog5sett5ings5[5slider5][5][5ima5ge5]";
var myRegexp = /\[(\d+)\][^\]]+]$/mg;
var match = myRegexp.exec(myString);
console.log(match[1]);

edited May 21, 2017 at 12:02

answered May 21, 2017 at 11:56

Pedro Lobito

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3 Comments

logi-kal Over a year ago

The OP wants only the number 5 to be matched.

Pedro Lobito Over a year ago

@horcrux it matches on group 1.

logi-kal Over a year ago

Sry, you are right, regex101 shows only the group 0.

logi-kal · Accepted Answer · 2017-05-21 12:00:28Z

0

Use this:

^.*\[(\d*)\]\[[^\]]*\]$

Where:

^ is the begin of the string
.* means any character
\[ and \] matches literal squared brackets
(\d*) is what you want to match
[^\]]* is the content of the last couple of brackets
$ is the end of the string

See an example:

var str = "5blog5sett5ings5[5slider5][5][5ima5ge5]";
var res = str.match(/^.*\[(\d*)\]\[[^\]]*\]$/);
console.log(res[1])

answered May 21, 2017 at 12:00

logi-kal

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