Parsing Json Variable into a link

Question

I would like to parse a json variable into another link, below is my code. However, i'v met this error, stating that "file_get_contents(0): failed to open stream: No such file or directory ". The directory is working if I type in manually.

   <?php
        $data = json_decode(file_get_contents('http://movie.com/movieOne?seatNum=' +  $movieSeat));
        $counter = count($data);
         echo "<script>movieBTN(x,y){ if (y == 'yes') { alert(x + 'Book Sucessful'); else { alert (x + 'Not sucessful');}</script>";

         for ($x = 0; $x < $counter; $x++) {
              echo  $data[$x]->avail . "<br>" ;
              $avail = $data[$x]->avail;
              echo "<button onclick = movieBTN('".$movieSeat.", ".$avail."')> Movie Seat </button>";
     }

        ?>

the $movieSeat is gotten from another json.

After I change from + to . I have this error "Undefined offset: 0" and "Trying to get property of non-object"

vardump

array(1) { ["avail"]=> string(3) "yes" }

yes, in the browser.. I have also tried it in the code as well, like change the change the link to (movie.com/movieOne?seatNum=1A) . Both works fine. However when I try to get the variable from another json , it doesn't work. Having the error as stated. — jamie
– jamie, Commented May 25, 2017 at 20:30
You do realize that browser sends bunch of headers when it sends response to server. And file_get_contents function dies not. My guess those guys defend from bots... — E_p
– E_p, Commented May 25, 2017 at 20:32
Use var_dump($movieSeat); before $data = json_decode(...); and see if you're getting the variable you expect. — helllomatt
– helllomatt, Commented May 25, 2017 at 20:33

AbraCadaver · Accepted Answer · 2017-05-25 21:02:25Z

2

Concatenation in PHP is done with a dot . not a plus +

so change this line to

$data = json_decode(file_get_contents('http://movie.com/movieOne?seatNum=' . $movieSeat));
// -  -  -  -  -  -  -  -  -  -  -  -  -  -  -  -  -  -  -  -  -  -  -  -  ^

Then just use foreach:

foreach($data as $v) {
    echo  $v['avail'];
}

edited May 25, 2017 at 21:02

AbraCadaver

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answered May 25, 2017 at 20:37

RiggsFolly

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7 Comments

jamie Over a year ago

why do I have error such as "Undefined offset: 0" and "trying to get property of non-object" when I change to .

RiggsFolly Over a year ago

Show us a var_export($data); please. Edit that into your question

RiggsFolly Over a year ago

string(2) "yes" makes no sense? "yes" is a 3 character string

jamie Over a year ago

Sorry, copied wrongly. I copied the "no".. I've changed

RiggsFolly Over a year ago

I see the edit. A copy/paste of a var_dump is safer than screwing it up

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