def test():
print 'test'
def test2():
print 'test2'
test = {'test':'blabla','test2':'blabla2'}
for key, val in test.items():
key() # Here i want to call the function with the key name, how can i do so?
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1possible duplicate of Calling a function of a module from a string with the function's name in Pythoncfi– cfi2015-09-14 09:44:25 +00:00Commented Sep 14, 2015 at 9:44
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4 Answers
You could use the actual function objects themselves as keys, rather than the names of the functions. Functions are first class objects in Python, so it's cleaner and more elegant to use them directly rather than their names.
test = {test:'blabla', test2:'blabla2'}
for key, val in test.items():
key()
Comments
John has a good solution. Here's another way, using eval():
def test():
print 'test'
def test2():
print 'test2'
mydict = {'test':'blabla','test2':'blabla2'}
for key, val in mydict.items():
eval(key+'()')
Note that I changed the name of the dictionary to prevent a clash with the name of the test() function.
4 Comments
Daniel DiPaolo
Oof, not sure why you'd ever use this over the "function objects as keys themselves" method. If anything, you may be introspecting using something like
hasattr, but never ever evalchrisaycock
@Daniel I didn't say it was pretty! :D
martineau
This works, but
eval() has a lot of overhead to use it just calling a function. There's other better, way more "Pythonic" ways...Karl Knechtel
... like, for example, looking up the name in
globals() and/or locals() perhaps? :)