There is urls.py pattern.
url(r'^notice/(?P<article>[0-9]\d+)/', web.views.notice),
Here is views.py
def notice(request, article):
data = article
return render(request, "notice.html")
However, web brower shows 404 Error. If I remove add parameter, it is ok.
What I am wrong?
Intended result (Blog style, not get parameter) /notice/1, /notice/2, ...
I think what is happening is that [0-9]\d+ is expecting at least a 2-digit number, one digit for the [0-9] and then one or more digits following that due to the \d+. I believe what you really want is just
url(r'^notice/(?P<article>\d+)$', 'web.views.notice')
'web.views.notice' as in my edit.article.I don't know why you use d???
url(r'^issue/(?P<issue_id>[0-9]+)$', views.issue, name='issue'),
url(r'^project/(?P<pk>.*)$', login_required(views.ProjectView.as_view()), name='project'),
Based on the question you asked, I am getting that you want to display the data on the template based on the parameter passed in the URL.Let me try to explain it step by step:
First lets say you have the following url:
url(r'^notice/(?P<article>\d+)$', views.notice,name="notice")
Now lets define the view for fetching the data from the model, based on the parameter in the URL, i am assuming you are passing the PK in the URL:
def notice(request, article):
data = YourModelName.objects.get(id=article)
//Passing back the result to the template
context={"article":data}
return render(request, "notice.html",context)
Now in your template you can access the data as such:
{{ article.field_name }}
Hope this helps you out!!!!
article? Is it a digit from 0 to 9?