TypeError: 'bool' object is not subscriptable Python 3

Question

I get the following error:

TypeError                                 Traceback (most recent call last)
C:\Users\levanim\Desktop\Levani Predictive\cosinesimilarity1.py in <module>()
     39 
     40 for i in meowmix_nearest_neighbors.index:
---> 41     top_ten = pd.DataFrame(similarity_matrix.ix[i,]).sort([i], 
ascending=False[1:6]).index.values
     42     meowmix_nearest_neighbors.ix[i,:] = top_ten
     43 
TypeError: 'bool' object is not subscriptable

for the following code. I'm new to Python and can't quite put my finger on how I have to change the syntax(if its a syntax python 3 problem). Anybody encounter this? I think it's to do with the ascending=False[1:6] portion and have spent some time banging my head against the wall. Hoping it's a simple fix but don't know enough

import numpy as np
import pandas as pd
from scipy.spatial.distance import cosine


enrollments = pd.read_csv(r'C:\Users\levanim\Desktop\Levani 
Predictive\smallsample.csv')

meowmix = enrollments.fillna(0)

meowmix.ix[0:5,0:5]

def getCosine(x,y) :
    cosine = np.sum(x*y) / (np.sqrt(np.sum(x*x)) * np.sqrt(np.sum(y*y)))
    return cosine

print("done creating cosine function")

similarity_matrix = pd.DataFrame(index=meowmix.columns, 
columns=meowmix.columns)
similarity_matrix = similarity_matrix.fillna(np.nan)

similarity_matrix.ix[0:5,0:5]
print("done creating a matrix placeholder")


for i in similarity_matrix.columns:
    for j in similarity_matrix.columns:
        similarity_matrix.ix[i,j] = getCosine(meowmix[i].values, 
meowmix[j].values)

print("done looping through each column and filling in placeholder with 
cosine similarities")


meowmix_nearest_neighbors = pd.DataFrame(index=meowmix.columns,
                                        columns=['top_'+str(i+1) for i in 
range(5)])

meowmix_nearest_neighbors = meowmix_nearest_neighbors.fillna(np.nan)

print("done creating a nearest neighbor placeholder for each item")


for i in meowmix_nearest_neighbors.index:
    top_ten = pd.DataFrame(similarity_matrix.ix[i,]).sort([i], 
ascending=False[1:6]).index.values
    meowmix_nearest_neighbors.ix[i,:] = top_ten

print("done creating the top 5 neighbors for each item")

meowmix_nearest_neighbors.head()

What exactly are you trying to do with the False[1:6] thing, anyway? — rm-vanda
– rm-vanda, Commented Jun 2, 2017 at 20:44

MarianD · Accepted Answer · 2017-06-02 21:29:21Z

5

Instead of

    top_ten = pd.DataFrame(similarity_matrix.ix[i,]).sort([i], 
ascending=False[1:6]).index.values

use

    top_ten = pd.DataFrame(similarity_matrix.ix[i,]).sort([i], 
ascending=False), [1:6]).index.values

(i. e. insert ), just after the False.)

False is the value of the sort() method parameter with meaning "not in ascending order", i. e. requiring the descending one. So you need to terminate the sort() method parameter list with ) and then delimit the 1st parameter of the DataFrame constructor from the 2nd one with , .

[1:6] is the second parameter of the DataFrame constructor (the index to use for resulting frame)

edited Jun 2, 2017 at 21:29

answered Jun 2, 2017 at 21:00

MarianD

14.4k12 gold badges50 silver badges61 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

meowmixplzdeliver Over a year ago

tried this: top_ten = pd.DataFrame(similarity_matrix.ix[i,]).sort([i], ascending=False), [1:6]).index.values and got the SyntaxError: invalid syntax

MarianD Over a year ago

Omit this second parameter, i. e. the part , [1:6], check the result and let know if it is acceptable.

meowmixplzdeliver Over a year ago

ValueError: Must have equal len keys and value when setting with an iterable

rm-vanda · Accepted Answer · 2021-01-16 21:42:24Z

2

Yeah, you can't do False[1:6] - False is a boolean, meaning it can only be one of two things (False or True)

Just change it to False and your problem will be solved.

the [1:6] construct is for working with lists. So if you had, for example:

theList = [ "a","b","c","d","e","f","g","h","i","j","k","l" ] 

print theList      # (prints the whole list)
print theList[1]   # "b"    
print theList[1:6] # ['b', 'c', 'd', 'e', 'f']

In python, this is called "slicing", and can be quite useful.

You can also do things like:

print theList[6:] # everything in the list after "f" 
print theList[:6] # everything in the list before "f", but including f

I encourage you to play with this using Jupyter Notebook - and of course, read the documentation

edited Jan 16, 2021 at 21:42

answered Jun 2, 2017 at 20:43

rm-vanda

3,1763 gold badges25 silver badges35 bronze badges

3 Comments

meowmixplzdeliver Over a year ago

hehe, after taking off [1:6], i know get the error: Must have equal len keys and value when setting with an iterable

Tibebes. M Over a year ago

I believe you meant to use # instead of //?

rm-vanda Over a year ago

Indeed! 3 years, and you're the first person to notice that. Thank you!

Collectives™ on Stack Overflow

TypeError: 'bool' object is not subscriptable Python 3

2 Answers 2

3 Comments

3 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

3 Comments

3 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related