php array filter function issue with variable

Question

I have a problem using a variable inside this array filter:

$lteam_id = 25;
$flt_lteam = array_filter($events, function($obj)

{
return $obj['team_id'] == $lteam_id && $obj['type'] == 'kick' && $obj['minute'] <= 75 ;
});

As soon as I replace $lteam_idwith 25 it works and I get a result. Using the variable results in an array(0) { }... Hope you can help me here on using the variables correctly.

php.net/manual/en/functions.anonymous.php#example-165

C3roe
– C3roe

2017-06-04 17:36:07 +00:00
Commented Jun 4, 2017 at 17:36 — C3roe
– C3roe, Commented Jun 4, 2017 at 17:36

Mohammad Hamedani · Accepted Answer · 2017-06-04 17:36:11Z

1

You use anonymous function, so you can use use statement to pass variable to it:

$lteam_id = 25;
$flt_lteam = array_filter($events, function($obj) use ($lteam_id)
{
    return $obj['team_id'] == $lteam_id && $obj['type'] == 'kick' && $obj['minute'] <= 75 ;
});

answered Jun 4, 2017 at 17:36

Mohammad Hamedani

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1 Comment

Robin Alexander Over a year ago

Great. Thanks! Works!

varuog · Accepted Answer · 2017-06-04 17:36:24Z

0

$lteam_id is not accessible in closure inside array_filter(). either pass the variable as argument of the closure or use using

$flt_lteam = array_filter($events, function($obj) using($lteam_id)

{
return $obj['team_id'] == $lteam_id && $obj['type'] == 'kick' && $obj['minute'] <= 75 ;
});

answered Jun 4, 2017 at 17:36

varuog

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