findIndex() javascript array object

Question

 var array = [{"one":1, "two":2},{"one":3, "two":4}];

            var result = array.findIndex(function (value) {
                if (value === 2) {
                    return false;
                }
                return true;
            });

            console.log(result);

i keep getting '0' in the console. how should i change (value ===2) ? i have tried change to (value === {"two":2}) but still return '0'.

is there any other array method that suitable ?

Because you are doing return true in every case. Also what does value === 2 means. value will be an object — Rajesh Dixit
– Rajesh Dixit, Commented Jun 6, 2017 at 6:49
which property do you like to check? there is no valuein the array. — Nina Scholz
– Nina Scholz, Commented Jun 6, 2017 at 6:49
value will never be 2 it will be either {"one":1, "two":2} or {"one":3, "two":4} — Jaromanda X
– Jaromanda X, Commented Jun 6, 2017 at 6:50
put a console.log into your findindex callback before the if()..and print the value passed to the callback. You might get some understanding as to what you the value is and what you are checking it with. — Yogesh Patil
– Yogesh Patil, Commented Jun 6, 2017 at 6:52
@JaromandaX i just want the index of {"one":1, "two":2} to show how should i change if (value === 2) ? — Zachary Lordford
– Zachary Lordford, Commented Jun 6, 2017 at 6:53

Nina Scholz · Accepted Answer · 2017-06-06 06:52:48Z

10

You need to check one of the properties of the objects of the array. Then return the result of the check.

var array = [{ one: 1, two: 2 }, { one: 3, two: 4 }],
    result = array.findIndex(function(object) {
        return object.two === 2;
    });

console.log(result);

answered Jun 6, 2017 at 6:52

Nina Scholz

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6 Comments

Jaromanda X Over a year ago

which, ironically, will also result in 0 being output - amazed the OP thought 0 was incorrect :p

Jaromanda X Over a year ago

Oh, I wasn't disagreeing with your answer :p

Zachary Lordford Over a year ago

sorry for asking @NinaScholz if the result less that zero means that it not match right ?

Nina Scholz Over a year ago

right it returns -1, because this number is not a real index of an array.

Zachary Lordford Over a year ago

thank you so much i'm still learning.. and u help a lot.. again thank u @NinaScholz

|

prasanth · Accepted Answer · 2017-06-06 06:52:54Z

0

Its first argument of the array .change with value.two .its object property not a array

var array = [{"one":1, "two":2},{"one":3, "two":4}];
            var result = array.findIndex(function (value) {
                               return value.two == 2;
            });
            console.log(result);

answered Jun 6, 2017 at 6:52

prasanth

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