I have two numpy 1d arrays, e.g:
a = np.array([1,2,3,4,5])
b = np.array([6,7,8,9,10])
Then how can I get one 2d array [[1,6], [2,7], [3,8], [4,9], [5, 10]]?
If you have numpy arrays you can use dstack():
import numpy as np
a = np.array([1,2,3,4,5])
b = np.array([6,7,8,9,10])
c = np.dstack((a,b))
#or
d = np.column_stack((a,b))
>>> c
array([[[ 1, 6],
[ 2, 7],
[ 3, 8],
[ 4, 9],
[ 5, 10]]])
>>> d
array([[ 1, 6],
[ 2, 7],
[ 3, 8],
[ 4, 9],
[ 5, 10]])
>>> c.shape
(1, 5, 2)
>>> d.shape
(5, 2)
np.stack((a, b), axis=-1), but your way is more compact.np.column_stack appears to be the fastest way to do this, see my comment on the question for details.np.dstack stacks arrays in the 3rd dimension. thus you'd be creating an unnecessary dimension. np.column_stack, or np.stack(...,axis=-1) are both more appropriate.axis=-1 and not +1?The answer lies in your question:
np.array(list(zip(a,b)))
Edit:
Although my post gives the answer as requested by the OP, the conversion to list and back to NumPy array takes some overhead (noticeable for large arrays).
Hence, dstack would be a computationally efficient alternative (ref. @zipa's answer). I was unaware of dstack at the time of posting this answer so credits to @zipa for introducing it to this post.
Edit 2:
As can be seen in the duplicate question, np.c_ is even shorter than np.dstack.
>>> import numpy as np
>>> a = np.arange(1, 6)
>>> b = np.arange(6, 11)
>>>
>>> a
array([1, 2, 3, 4, 5])
>>> b
array([ 6, 7, 8, 9, 10])
>>> np.c_[a, b]
array([[ 1, 6],
[ 2, 7],
[ 3, 8],
[ 4, 9],
[ 5, 10]])
You can use zip
np.array(list(zip(a,b)))
array([[ 1, 6],
[ 2, 7],
[ 3, 8],
[ 4, 9],
[ 5, 10]])
zipcan be faster than calling Numpy functions, but for longer arrays the Numpy functions are much faster, withcolumn_stackbeing the fastest in my tests. Eg, for arrays of length 1000,column_stackis about 1000 times faster thanzip. Here's some relevant timeit code.