Json to url with php

Question

In my $output there is this:

{
  "status" : "success",
  "data" : {
    "network" : "BTC",
    "addresses" : [
      {
        "user_id" : 0,
        "address" : "3ABR5GohqyXzf2zebYwjmLuwV7vtFZw1BZ",
        "label" : "default",
        "available_balance" : "0.00000000",
        "pending_received_balance" : "0.00000000"
      }
    ]
  }
}

But now I want it to get to redirect like: https://example.com/index.php?status=succes&network=BTC

etc. etc.

But $output can change to like:

{
  "status" : "success",
  "data" : {
    "network" : "BTC",
    "available_balance" : "0.00000000",
    "pending_received_balance" : "0.00000000"
  }
}

But then I still want it to work. I don't know PHP enough for this, so I want to ask:

How to do this?

So, you want to get those values from that json and generate an url? — Jerodev
– Jerodev, Commented Jun 8, 2017 at 12:14
json_decode will turn it into an array for you. Then you just find the array elements with the keys that you need. — ADyson
– ADyson, Commented Jun 8, 2017 at 12:16
So you just want status and network from the possible JSONStrings right? And those 2 will always be there Right? — RiggsFolly
– RiggsFolly, Commented Jun 8, 2017 at 12:17
@ADyson It changes everytime, and I want all to get in the url.. — intapromotie
– intapromotie, Commented Jun 8, 2017 at 12:24

MrCode · Accepted Answer · 2017-06-08 12:18:50Z

1

Simply json_decode() and access the status and network properties:

$decoded = json_decode($output);
header('Location: https://example.com/index.php?status=' . urlencode($decoded->status) . '&network=' . urlencode($decoded->data->network));
exit();

answered Jun 8, 2017 at 12:18

MrCode

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1 Comment

ADyson Over a year ago

@intapromotie in that case you did something wrong. 500 means internal server error. So switch PHP error reporting on (you can google how) and find out what the real error is.

jared · Accepted Answer · 2017-06-08 12:20:24Z

0

Get the data in the json as an array:

$url = 'https://example.com/index.php?status=' . $status;
foreach($data as $param->$value) {
    $url += '&' . $param . '=' . $value
}
header('Location:' $url);

Been a while since i've worked in php but this should handle a varying amount of parameters.

answered Jun 8, 2017 at 12:20

jared

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2 Comments

intapromotie Over a year ago

So, I must to add at $data my json. And what is $status?

jared Over a year ago

Check the web server error log to see more details about the problem.

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