pass values from javascript function to php file is not working for me

Question

i want to send two variables values from one file, which have XML code where i have function which include the php file, so i want it should include this php file with my passed values, am doing like following way

function load(){
    var id=cn;
    var name="zuni";

    downloadUrl('info.php?id2=id&name2=name', function(data) {

    });

code in info.php

if (isset($_GET['id'])) {
    $id2 = $_GET['id2'];
    $name2 = $_GET['name2']; 
    echo "id is :". $id2;
    echo "name is :". $name2; 
}

its output is showing like this

id is:id
name is: name

its not displaying variable value but variable name, i want its value not name any one can check whats wrong with this code ?

What? In id2=id&name2=name value of id2 is id, same to name2. And scripts outputs just what you've passed to it. — u_mulder
– u_mulder, Commented Jun 11, 2017 at 9:51
@u_mulder i want to to pass value of name2="zuni" not name2=name — m junaid
– m junaid, Commented Jun 11, 2017 at 9:53

Allan Chua · Accepted Answer · 2017-06-11 09:53:14Z

2

This is happening because the request URL that you are passing have literal values

  'info.php?id2=id&name2=name'.

To solve the problem you have to use the code below instead:

  "info.php?id2=" + id + "&name2=" + name

answered Jun 11, 2017 at 9:53

Allan Chua

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1 Comment

Allan Chua Over a year ago

@mjunaid It is always my pleasure to give back to the community ;)

ttncrch · Accepted Answer · 2017-06-11 09:54:55Z

0

if you want your code to work you shoud use back tick to inject your variable in your download request :

downloadUrl(`info.php?id2=${id}&name2=${name}`, function(data) {

or use the string concatenation

downloadUrl('info.php?id2=' + id + '&name2=' + name, function(data) {

you actually pass id and name to your GET resquest. This is normal that your server get id and name.

answered Jun 11, 2017 at 9:54

ttncrch

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