How to list files in a directory in python?

Question

I am unable to list files in a directory with this code

import os
from os import listdir
def fn():       # 1.Get file names from directory
    file_list=os.listdir(r"C:\Users\Jerry\Downloads\prank\prank")
    print (file_list)

 #2.To rename files
     fn()

on running the code it gives no output !

Is your function even being called? From what you've posted, it looks like the call to fn() is inside the definition of fn() — khelwood
– khelwood, Commented Jun 12, 2017 at 8:13

nikpod · Accepted Answer · 2017-06-12 08:20:10Z

13

The function call fn() was inside the function definition def fn(). You must call it outside by unindenting the last line of your code:

import os
def fn():       # 1.Get file names from directory
    file_list=os.listdir(r"C:\Users")
    print (file_list)

 #2.To rename files
fn()

edited Jun 12, 2017 at 8:20

answered Jun 12, 2017 at 8:19

nikpod

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1 Comment

kuro Over a year ago

Remove the from os import listdir line too

guidot · Accepted Answer · 2017-06-12 08:48:47Z

1

You should use something like this

for file_ in os.listdir(exec_dir):
  if os.path.isdir(exec_dir+file):
        print file_

I hope this is useful.

edited Jun 12, 2017 at 8:48

guidot

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answered Jun 12, 2017 at 8:17

i.q.

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1 Comment

khelwood Over a year ago

edit your answer, highlight the code, press ctrl k .

BugsCreator · Accepted Answer · 2022-11-23 09:11:04Z

0

if you want to list all files including sub dirs. you can use this recursive solution

import os
def fn(dir=r"C:\Users\aryan\Downloads\opendatakit"): 
    file_list = os.listdir(dir)
    res = []
    # print(file_list)
    for file in file_list:
        if os.path.isfile(os.path.join(dir, file)):
                res.append(file)
        else:
            result = fn(os.path.join(dir, file))
            if result:
                res.extend(fn(os.path.join(dir, file)))
    return res


res = fn()
print(res)
print(len(res))

answered Nov 23, 2022 at 9:11

BugsCreator

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