Typescript - How to convert the string ("console.log") to the function (console.log)

Question

Using typescript, I need to convert some strings like "Math.floor" and "console.log" to the functions Math.floor and console.log, in order to be able to use those functions when passed as a string parameter.

For example

applyFunction ("Math.floor", 4.2); // => Math.floor(4.2) => 4
applyFunction ("console.log", "Hi"); // => console.log("Hi") => Hi

And so on.

I tried adding them as keys and values in an object and scanning the object whenever needed. But since I don't have the time to continuously search for and add all existing Typescript functions, I'm looking for a more comprehensive approach.

nicholaswmin · Accepted Answer · 2017-06-12 14:17:43Z

3

FWIW you can use eval() to parse strings as code.

Example:

eval("console.log('foo')")

That being said, I'd advice you to be careful when using eval().

edited Jun 12, 2017 at 14:17

answered Jun 12, 2017 at 14:11

nicholaswmin

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1 Comment

TamerB Over a year ago

For me it worked as: eval("console.log")('foo'); Thanx alot

Fals · Accepted Answer · 2017-06-12 14:17:25Z

1

If you are using the browser you can do:

window['Math']['floor'](4.2);
window['console']['log']('Hi');

Make sure you iterate over the namespaces, eval(string) works better.

edited Jun 12, 2017 at 14:17

answered Jun 12, 2017 at 14:13

Fals

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5 Comments

nicholaswmin Over a year ago

I've posted an answer below that uses eval but I like this one better

Fals Over a year ago

@NicholasKyriakides eval(string) does the work better, this one is just another approach it you are in the browser, but is difficult because you must iterate over namespaces

epascarello Over a year ago

why is it difficult, simple split and reduce

TamerB Over a year ago

eval('Math.floor')(4.2) was much easier for my situation. Thanks a lot

Jonas Wilms Over a year ago

concerning espacarellos comment "Math.floor".split(".").reduce((o,i)=>o[i],window)(5)

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