error during array creation in bash

Question

I have a couple of files with certain keywors (one is MAT1). For this key word i like to read the ID corresponding to it, put this together with the filename into an array. I tried the following (I am not very familiar with bash programming):

#!/bin/bash
Num=0
arr=( $(find . -name '*.mat' | sort) )

for i in "${arr[@]}"
do

  file=$(basename "${i}")

  while read -r line
  do

  name="$line"
  IFS=' ' read -r -a array <<< "$line"
    for index in "${!array[@]}"
    do

      if [ ${array[index]} == "MAT1" ]
      then
        out[$num] = "${array[index+1]} $file "
        let num++
        #printf "%-32s %8i\n" "$file" "${array[index+1]}"
      fi

    done

  done < "$i"

done

With this get the message

make_mat_list.bsh: line 21: out[0]: command not found

make_mat_list.bsh: line 21: out[1]: command not found

What is wrong here?

Inian · Accepted Answer · 2017-06-14 06:54:27Z

1

bash is white-space sensitive, your line below cannot have spaces.

out[$num] = "${array[index+1]} $file "

As for the reason for the error, the shell treats that particular line as the first word being a command out[$num] i.e. out[1]..etc and rest of it as arguments to it = and "${array[index+1]} $file ", which does not make any sense. Remove the spaces and do jsut

out[$num]="${array[index+1]} $file"

answered Jun 14, 2017 at 6:54

Inian

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