Trouble accessing multiple array data in php

Question

I am putting the data in multiple array in php and trying to access it through key value pair logic but not getting success

Here's the output when I'm printing the array with print_r:

Array ( 
    [0] => Array ( 
        [33] => Coca Cola Products 
    ) 
    [1] => Array ( 
        [1] => Agricultural products, Food and Beverages 
    ) 
)

The code I'musing:

foreach ($data as $key=>$option)
{
    echo $key;
}

output required:

33 coca cola products
1 Agricultural products, Food and Beverages

In my for-loop for populating data I'm doing this:

$data[] = array($loop['category_id'] => $loop['category_name']);

Now wanted to get category id and category name

I'm guessing that category_id's are unique? Why not build you're array like this instead: $data[$loop['category_id']) = $loop['category_name']; and just do this in your foreach: echo $key . ' ' . $option; — M. Eriksson
– M. Eriksson, Commented Jun 16, 2017 at 6:08

Nigel Ren · Accepted Answer · 2017-06-16 06:21:52Z

2

When you populating the array...

data[] = array($loop['category_id'] => $loop['category_name']);

Your creating each element as an array, which is why you end up with the end result you have.

If you used

$data[$loop['category_id']] = $loop['category_name'];

You would see that the array is created at 1 level of depth. Use print_r on this and you will see the difference. This will mean when you iterate over with the foreach it will use the keys you used to add the data and give the values your after.

edited Jun 16, 2017 at 6:21

answered Jun 16, 2017 at 6:15

Nigel Ren

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3 Comments

M. Eriksson Over a year ago

If you're gonna copy/paste my comment, make sure you fix the error in it. :-) It should be $data[$loop['category_id']] and not $data[$loop['category_id']) (the last parenthesis).

Nigel Ren Over a year ago

The problem I have with comments is that they don't always explain what the problem is, and sorry about copy - it's caffeine hasn't kicked in yet and typing is hard work :-/

M. Eriksson Over a year ago

Didn't mean to imply that you did anything wrong. Just thought it was a bit funny. :-)

LF-DevJourney · Accepted Answer · 2017-06-16 06:28:44Z

1

Your $data is an array of array, you should do it like this, live demo.

foreach ($data as $v)
{
    echo key($v) . ' ' . current($v) . "\n";
}

answered Jun 16, 2017 at 6:28

LF-DevJourney

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Comments

Roopendra · Accepted Answer · 2017-06-16 06:52:52Z

0

This can be done as below

$data = array(array('33'=>"Coca Cola Products"),array("1"=>"Agricultural products, Food and Beverages"));

foreach ($data as $key=>$option)
{
        foreach($option as $k=>$v){
                echo "\n". $k ." ". $v;
        }
}

edited Jun 16, 2017 at 6:52

Roopendra

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answered Jun 16, 2017 at 6:33

hundredbytes

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