How to replace value of multidimensional array when key present in another array?

Question

I have one array with state codes and their full names, like this:

$first_array=array("AB"=>"Alberta","BC"=>"British Columbia");

I have another array with ids and state codes, like this:

$result_array=array(15=>array("ad_id"=>15,"state code"=>"AB"));

I want to replace the state code values in $result_array with the corresponding "full name" in $first_array.

If there is no corresponding value in $first_array then the state code in $result_array should remain unchanged.

This is my expected result:

$result_array=array(15=>array("ad_id"=>15,"state code"=>"Alberta"));

my result array, Array ( [15] => array ( [ad_id] => 15 [state code] => AB ) ) but I want below array Array ( [15] => array ( [ad_id] => 15 [state code] => Alberta ) ) — bdevloper
– bdevloper, Commented Jun 20, 2017 at 11:37
try using array_search() for finding key value and replace it with another variable — Gaurang Sondagar
– Gaurang Sondagar, Commented Jun 20, 2017 at 11:39
array_walk($resultArray, function (&$value) use ($first_array) { $value['state_code'] = $first_array[$value['state_code']]; }); — Mark Baker
– Mark Baker, Commented Jun 20, 2017 at 11:45

Sougata Bose · Accepted Answer · 2017-06-20 11:48:30Z

1

This should work -

$first_array= array("AB"=>"Alberta","BC"=>"British Columbia");

$second_array = array(
15 => array ( 'ad_id' => 15, 'state code' => 'AB' ) ,
16 => array ( 'ad_id' => 16, 'state code' => 'CD' ) 
);

$new = array_map(function($a) use($first_array) {
    return array(
        'ad_id' => $a['ad_id'],
        'state code' => !empty($first_array[$a['state code']]) ? $first_array[$a['state code']] : $a['state code'],
    );
}, $second_array);

print_r($new);

Output

Array
(
    [15] => Array
        (
            [ad_id] => 15
            [state code] => Alberta
        )

    [16] => Array
        (
            [ad_id] => 16
            [state code] => CD
        )

)

answered Jun 20, 2017 at 11:48

Sougata Bose

31.8k8 gold badges52 silver badges89 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

mickmackusa · Accepted Answer · 2017-06-20 14:01:31Z

Input:

$first_array=["AB"=>"Alberta","BC"=>"British Columbia"];
$result_array=[
    15=>['ad_id'=>15,'state code'=>'AB'],
    16=>['ad_id'=>16,'state code'=>'BC'],
    17=>['ad_id'=>17,'state code'=>'NY']
];

Method #1 - array_walk()

array_walk($result_array,function(&$a)use($first_array){
    if(isset($first_array[$a['state code']])){  // only overwrite state code if full name is available
        $a['state code']=$first_array[$a['state code']];
    }
});

Method #2 - foreach()

foreach($result_array as $k=>$a){
    if(isset($first_array[$a['state code']])){  // only overwrite state code if full name is available
        $result_array[$k]['state code']=$first_array[$a['state code']];
    }   
}

Output (from either method): var_export($result_array);

array (
  15 => 
  array (
    'ad_id' => 15,
    'state code' => 'Alberta',
  ),
  16 => 
  array (
    'ad_id' => 16,
    'state code' => 'British Columbia',
  ),
  17 => 
  array (
    'ad_id' => 17,
    'state code' => 'NY',
  ),
)

Collectives™ on Stack Overflow

How to replace value of multidimensional array when key present in another array?

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related