Combining array of strings in Javascript two at a time

Question

I have an array of strings, how I can make combination of elements two at a time separated by underscore.

var array = ['a', 'b', 'c']; the output should be ['a_b', 'a_c', 'b_c']

How I can do this in Javascript?

Please note that this is different from Permutations in JavaScript? since we need a combination of two and cannot be array elements cannot be replicated.

Thanks.

It should not combine same elements like a_a, and if b_c exist then it should not contain c_b. — Unnikrishnan
– Unnikrishnan, Commented Jun 20, 2017 at 16:27

Tyler Roper · Accepted Answer · 2017-06-20 16:30:07Z

2

You can use nested loops to achieve something like that:

var arr = ['a', 'b', 'c'];
var newArr = [];
    
for (var i=0; i < arr.length-1; i++) {        //Loop through each item in the array
    for (var j=i+1; j < arr.length; j++) {    //Loop through each item after it
        newArr.push(arr[i] + '_' + arr[j]);   //Append them
    }
}
    
console.log(newArr);

I've elected to mark this as a community post because I think a question that shows no attempt shouldn't merit reputation, personally.

answered Jun 20, 2017 at 16:30

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Tyler Roper

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Comments

Dij · Accepted Answer · 2017-06-20 16:28:14Z

1

A solution could be:

function combine(arr) {

    if (arr.length === 1) {
        return arr; // end of chain, just return the array
    }

    var result = [];

    for (var i = 0; i < arr.length; i++) {
        var element = arr[i] + "_";
        for (var j = i+1; j < arr.length; j++) {
            result.push(element + arr[j]);
        }
    }
    return result;
}

answered Jun 20, 2017 at 16:28

Dij

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Comments

Cristian Batista · Accepted Answer · 2017-06-20 16:27:35Z

0

It should be an double for, something like this:

var output = [];
var array = ['a', 'b', 'c'];
    for(var i = 0; i < array.length; i++){
        for(var j = 0; j < array.length; j++) {
           output.push(array[i] + "_" + array[j]);
        }
    }

The output is:

["a_a", "a_b", "a_c", "b_a", "b_b", "b_c", "c_a", "c_b", "c_c"]

answered Jun 20, 2017 at 16:27

Cristian Batista

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5 Comments

ibrahim mahrir Over a year ago

Please read the comments bellow the question for more details.

geo Over a year ago

This does not produce the desired output

Unnikrishnan Over a year ago

Sorry I didn't mention it in the question, it should not combine same elements like a_a, and if b_c exist then it should not contain c_b.

Cristian Batista Over a year ago

In that case will be useful add: if(array[i] != array[j]) before the push

Cristian Batista Over a year ago

This is the output: ["a_b", "a_c", "b_a", "b_c", "c_a", "c_b"]

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