I need to insert a space after every character of a string.
i.e.
String name = "Joe";
should become: "J o e"
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9 Answers
Shorter would be using a regex:
System.out.println("Joe".replaceAll(".(?!$)", "$0 "));
4 Comments
Wouter Coekaerts
This has the added advantage (compared to looping over the characters) that it doesn't break surrogate pairs.
StuperUser
Now you have two problems. stackoverflow.com/questions/1038186/…
StuperUser
@Wouter: what do you mean by surrogate pairs?
Wouter Coekaerts
@StuperUser: Pairs of characters used to represent characters outside the "Basic Multilingual Plane". See class description on download.oracle.com/javase/6/docs/api/java/lang/Character.html
For Android & Kotlin users, if you want to add space after every X characters then use this
val stringWithSpaceAfterEvery4thChar = stringWith12Chars?.replace("....".toRegex(), "$0 ")
Here I added 4 dots in method to add space after every 4th character in my whole string. If you want space after every 2 characters then add only 2 dots in the method.
My variables:
stringWith12Chars = "123456789012"
and the output would be,
stringWithSpaceAfterEvery4thChar = "1234 5678 9012"
2 Comments
TootsieRockNRoll
this is just perfect!
Himani
You gave proper logic.
Something like:
String joe = "Joe";
StringBuilder sb = new StringBuilder();
for (char c: joe.toCharArray()) {
sb.append(c).append(" ");
}
System.out.println(sb.toString().trim());
1 Comment
Karl Knechtel
A slight optimization:
sb.setLength(sb.length() > 0 ? sb.length() - 1 : 0).toString(); i.e. trim the builder, not the result.This will space out all letters in each word and not between words
"Joe Black".replaceAll("\\B", " ") -> "J o e B l a c k"
This will put space for each character (including original spaces)
"Joe Black".replaceAll("\\B|\\b", " ") -> " J o e B l a c k "
Comments
Using kotlin
val textToBeDevided = "123456789"
textToBeDevided
.subSequence(1, textToBeDevided.length)
.chunked(3) // group every 3 chars
.joinToString(" ") // merge them applying space
1 Comment
Ilya Serbis
.subSequence call is redundant because String is already a CharSequence. Moreover, indexes in strings start from 0 so you've lost "1" in an output.char[] stringArray = strOrig.toCharArray();
StringBuilder sb = new StringBuilder();
for(int index=0; index < stringArray.length; index++) {
sb.append(stringArray[index]);
sb.append(" ");
}
Comments
Solution without regex
name.chars().mapToObj(i -> (char) i + " ").collect(Collectors.joining()).strip()
Don't like regex because compile method slow
Comments
You can convert Joe to char[] by using String's toCharArray() then traverse char[] to grab the char into another char[] and as you add the char to the second char[], you add a space character '" "'. Set a if-else within the loop to detect the last character so that you wouldn't add a space character by accident behind the last character. Use a String to valueOf() the resulting char[] to turn it into a String object.
Comments
Removing the final space:
String joe = "Joe";
StringBuilder sb = new StringBuilder();
String sep = "";
for (char c: joe.toCharArray()) {
sb.append(sep).append(c);
sep = " ";
}
System.out.println(sb.toString());
