var timeCost =[];
var ride_time = 30;
var cost_per_minute = [0.2, 0.35, 0.4, 0.45];
for (let i = 0; i < cost_per_minute.length; i++ ){
timeCost.push(cost_per_minute[i]*ride_time)
}
console.log(timeCost)
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1timeCost.push(cost_per_minute[i]*ride_time) ... please have a look at the console first, it will tell you that [i]* is invalidJonas Wilms– Jonas Wilms2017-06-23 17:12:02 +00:00Commented Jun 23, 2017 at 17:12
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1The length of the "cost_per_minute" value, is 4, so this loop is never going to run!Iain J. Reid– Iain J. Reid2017-06-23 17:13:06 +00:00Commented Jun 23, 2017 at 17:13
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3 Answers
This is far more concise with .map():
let cost_per_minute...
const ride_time = 30;
let timeCost = cost_per_minute.map(x => x * ride_time);
Comments
var ride_time = 30;
var cost_per_minute = [0.2, 0.35, 0.4, 0.45]
var timeCost = cost_per_minute.map(function(i){return i* ride_time})
console.log(timeCost)
Comments
Two places in your code:
The 2nd part of a for loop is commonly a condition of the counter (i.e. i) being less than the total count of the array (.ie. cost_per_minute.length)
for (var i = 0;
i < cost_per_minute.length;i++ ){
The syntax for an element within an array is nameOfArray[i] with i as the variable index number.
timeCost.push(
cost_per_minute[i]*ride_time)
}
var timeCost =[];
var ride_time = 30;
var cost_per_minute = [0.2, 0.35, 0.4, 0.45];
for (let i = 0; i < cost_per_minute.length; i++ ){
timeCost.push(cost_per_minute[i]*ride_time)
}
console.log(timeCost)