C++ initialization of struct containing an array

Question

I have a structure that more or less follows this pattern:

struct sTruct {
   int count;
   struct {
       int A;
       int B;
       int C;
   } array[];   //count is the size of this array
};

I would like to be able to initialize these with something like the following syntax:

sTruct gInit1 = { 2, { {1,2,3},{4,5,6} }};

Really, that initialization syntax (or rather, the compactness of it) is more important than the specific struct layout. I do not have access to the standard containers (embedded platform), but I might be able to replicate some of their behavior if needed.

In final form, I would like to initialize an array of roughly 300 of these sTruct containers at once, just to add one more level of parenthesis.

Edward Strange · Accepted Answer · 2010-12-17 17:27:08Z

7

You can't do it. If you gave the array a size you could. An alternative might be:

template < int size >
struct sTruct
{
  struct { int a, int b, int c } array[size];
};
sTruct<2> gInit1 = {{1,2,3},{4,5,6}};

But, of course, all your sTructs are different types and so it may not be what you want. Your only other alternative is going to have to be free-store based and won't give you that syntax until initialization lists in 0x.

edited Dec 17, 2010 at 17:27

answered Dec 17, 2010 at 17:21

Edward Strange

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2 Comments

jkerian Over a year ago

I suppose stuffing different sized sTructs into the same array doesn't make much sense in the first place. I may use something like this template, although I still need to add the "size" variable itself to the outer struct.

Edward Strange Over a year ago

If you like this answer you may as well use boost::array. It's more or less exactly my answer but can hold anything and acts like a standard container (except it has a static size and can be initialized with aggregate syntax).

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