php while within array

Question

I have to populate a json with PHP. I have this structure:

$request = array(
      "api_uid" => "000000", 
      "api_key" => "xxxxxx", 

      "lista_articoli" => array(

      //loop 


      array(
"nome" => "Acconto",
      "descrizione" => "Acconto per la festa del " .$datafesta,
      "prezzo_lordo" => $importo,
      "cod_iva" => 0 
        )

   // end loop

I try to use while inside array, but it's an error:

while($row = $tipologia->fetch(PDO::FETCH_ASSOC)) {

      array("nome" => $row['nome'],
      "descrizione" => $row['desc'],
      "prezzo_lordo" => $row['prezzo_lordo'],
      "cod_iva" => 0 
        ),
                     }

How can i loop my data in correct way inside array?

you can not loop in inside array

lalithkumar
– lalithkumar

2017-06-24 14:01:40 +00:00
Commented Jun 24, 2017 at 14:01 — lalithkumar
– lalithkumar, Commented Jun 24, 2017 at 14:01

localheinz · Accepted Answer · 2017-06-24 16:34:50Z

2

You can't loop inside array.You need to create array and assign value to them by keys in loop.Try like below :

while ($row = $tipologia->fetch(PDO::FETCH_ASSOC)) {
    $request['lista_articoli'][] = [
        'nome' => $row['nome'],
        'descrizione' => $row['desc'],
        'prezzo_lordo'] => $row['prezzo_lordo'],
        'cod_iva' => 0,
    ];
}

edited Jun 24, 2017 at 16:34

localheinz

9,6422 gold badges37 silver badges44 bronze badges

answered Jun 24, 2017 at 14:04

lalithkumar

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7 Comments

localheinz Over a year ago

This will just keep overriding the values, you probably want to add an array on each iteration.

lalithkumar Over a year ago

no that is not what he asked...He just showed one array and assigning inside array which is wrong..

frwebdev Over a year ago

Thank you, but I can not understand where to put your code into my structure

lalithkumar Over a year ago

you can put anywhere where is appropriate..Please accept the answer by click the tick mark @frwebdev

frwebdev Over a year ago

i try to put your code inside my loop area, but i still have the same error, because i have array right after ...$request = array(.... Sorry for my low level in php

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