Python - How to run section of code depending on parameters

Question

I am new in Python script. I would like to be a bit pro in my code writing. Basically, I have a script that has a functionally and I would like to add new functionality.

my code looks a bit like:

const declaration
CONST1 = ....
CONST2 = ....
CONST3 = ....
CONST4 = ....
CONST5 = ....
CONST6 = ....
CONST7 = ....


function declaration
def f1:
    ....

def f2:
    ....
def f3:
    ....
def f5:
    ....
def f7:
    ....
def f8:
    ....
def f0:
    ....

first part 
logic
logic
logic
logic
logic
logic
logic
    logic


second part 
.......
.......

I want to add new functionality down here, so that when the script runs with certain params, the first parts or second runs depending on params.

I know I could use if ... else to do this, but would like to know if there is a more professional way to do this. so that the code would be more maintainable and easy to add things. Can you please give me some advice?

Put them into functions and call the right one depending on your parameters — BoilingFire
– BoilingFire, Commented Jun 28, 2017 at 12:07
You are asking how to do control flow this is a very broad question, depending on your data/size of application, you can use different approaches out of loads of possibilities: en.wikipedia.org/wiki/Control_flow — user1767754
– user1767754, Commented Jun 28, 2017 at 12:10

score 1 · Accepted Answer · 2017-06-28 12:38:56Z

1

In this case you should to use dictionary

for example:

CONST1 = 'CONST1'
CONST2 = 'CONST2'

def f1():
    return 'Hello from f1 function'

def f2():
    return "Hello from f2 function"

my_data = {
    'CONST1': f1,
    'CONST2': f2,
}

def run(key):
    # If there is no key, just return message
    # Or use try/catch
    if key not in my_data.keys():
        return 'Oops, I can\'t find the key'

    # Here we get a value via key, and call function via parentheses
    return my_data[key]()

print(run('CONST1'))

edited Jun 28, 2017 at 12:38

answered Jun 28, 2017 at 12:31

user5639219

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Comments

Jeril · Accepted Answer · 2017-06-28 12:11:23Z

0

You can use get method of Python Dictionary.

def f(x):
    return {
        'a': 1,
        'b': 2,
    }.get(x, 9)    # 9 is default if x not found

or

options = {
    0 : First,
    1 : Second,
}
options[num]()

answered Jun 28, 2017 at 12:11

Jeril

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