Storing values to an Array using foreach loop

Question

My code:

$videos_key = array();
foreach($result[$x]["videos_key"] as $videoskey => $result[$x]["videos_key"] ) 
    {
        $videos_key[$videoskey] = $result[$x]["videos_key"];
    }


print_r($videos_key);

I want to store all values inside $result[$x]["videos_key"] to $videos_key variable

But i am getting this error:

Warning: Invalid argument supplied for foreach()

You should first have a look at PHP's documentation: foreach — Javier Arias
– Javier Arias, Commented Jun 28, 2017 at 13:48
$result[$x]["videos_key"] what is $x and is this an array — ArtisticPhoenix
– ArtisticPhoenix, Commented Jun 28, 2017 at 14:16
I am using this code inside an forloop. $x is like 0,1,2,3 @ArtisticPhoenix — John Doo
– John Doo, Commented Jun 28, 2017 at 14:18

René Höhle · Accepted Answer · 2017-06-28 13:28:52Z

2

That syntax you use is to split your array in key value pairs.

$videos_key = array(
   array('id' => 1, 'value' => 'test')
);

$video_keys_out = array();

foreach($videokey as $key => $value) {
    $videos_keys_out[$key] = $value;
}

something like that. I don't know the rest of your code. So with that syntax you fetch the id and value keypair form the first array and you can work with them.

answered Jun 28, 2017 at 13:28

René Höhle

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1 Comment

John Doo Over a year ago

Hey videokey is not defined variable. So i am getting 2 errors Notice: Undefined variable: videokey Warning: Invalid argument supplied for foreach()

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