Replace any beginning character instance with empty string

Question

Say I have a string like so:

let v = '/////bar/foo'

how can I just replace the slashes at the beginning of v with ''?

I am looking to get this:

let result = 'bar/foo'

How do you define "any beginning character instance"? It seems you want to replace all non–alphabetic characters, which might be /^[^a-z]+/i. — RobG
– RobG, Commented Jun 30, 2017 at 1:57

wbadart · Accepted Answer · 2017-06-30 01:46:29Z

4

let r = v.replace(/^\/+/, '');

The regular expression finds one or more / at the beginning of the string and replaces that pattern with ''.

answered Jun 30, 2017 at 1:46

wbadart

3,0211 gold badge18 silver badges29 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

vol7ron · Accepted Answer · 2017-06-30 12:04:14Z

1

A little regex and you're done:

let v = '/////bar/foo';

console.log( v.replace(/^\/+/,'') );

answered Jun 30, 2017 at 2:03

vol7ron

42.3k22 gold badges126 silver badges178 bronze badges

koralarts · Accepted Answer · 2017-06-30 01:59:04Z

0

let parsed = v.replace(/^[^a-zA-Z\d]+/, '')

This will replace any character that is not alphanumeric

or as pointed out by RobG

/^\W+/

answered Jun 30, 2017 at 1:57

koralarts

2,1125 gold badges30 silver badges49 bronze badges

/^\W+/ is shorter. ;-)

@RobG Oh fine :p