i have a function and a local variable declared inside it, i don't want to declare it as global because some functions are also using its default value
function default()
{
var val="me";
//others.....
}
is there a way aside from this using prototyping
function default(value)
{
var val=value;
//others.....
}
something like,
default.prototype.val = "you";
re-constracting
No. It is not possible to declare a variable inside the function (var myVar) and then access it once the function has ended. This is because the variable is created within the function's lexical scope and is undefined outside of it. Here is some more info on how scoping works: https://scotch.io/tutorials/understanding-scope-in-javascript
As for your proposed solution default.prototype.val this does not work because default is a function and does not have properties or a prototype. This is something an object would have.
As others have indicated, you may pass in a variable or use default values, but it seemed your were asking about accessing a variable created inside the function and that is not doable. You need to return the value or pass in a variable which is modified by the function.
function name(s) {
return s || "me"
}
console.log(name())
console.log(name("you"))You can use the default values to the arguments
function default(value ="you")
{
var val=value;
//others.....
}
https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Functions/Default_parameters
usage will be something like this
default(); // value will be "you"
default("me"); value will be "me"
try this one
function defaultfun (value="") {
var val = "me";
alert("new value:"+value+"\n old value:"+val);
}
defaultfun();
defaultfun("you");