Remove element with array_diff_key() by one specific key

Question

I want to remove one ore more array element using array_diff_key() with one specific key but the result is different

$a = [
        ['value' => 1, 'text' => '1 Hour'],
        ['value' => 12, 'text' => '12 Hour'],
        ['value' => 24, 'text' => '1 Day'],
    ];

$b = [
        ['value' => 12],    
    ];

$c = array_diff_key($a, $b);

//print_r($c);
//return Array ( [1] => Array ( [value] => 12 [text] => 12 Hour ) [2] => Array ( [value] => 24 [text] => 1 Day ))

Expected result

Array ( 
      [1] => Array ( 
        [value] => 1 
        [text] => 1 Hour ) 
      [2] => Array ( 
        [value] => 24 
        [text] => 1 Day ) 
)

I can get expected result if I set text in $b but in this case I don't want to set text.

Where i'm doing wrong? other solution is wellcome.

Thanks in advance

PS: $b can be one or more element

Based on what I understand, you simply want to remove the nested array in $a where the value matches that of the incoming array $b, right? — Terry
– Terry, Commented Jul 1, 2017 at 10:52
$b is an array or just you want to search 12 in text key ? — Sahil Gulati
– Sahil Gulati, Commented Jul 1, 2017 at 10:53
@sahil, $b is array and I want to remove $a element which match $b — Dark Cyber
– Dark Cyber, Commented Jul 1, 2017 at 10:59

Jaydeep Mor · Accepted Answer · 2017-07-01 10:57:13Z

2

Try below code,

Check thorough loop.

<?php
    $a = [
            ['value' => 1, 'text' => '1 Hour'],
            ['value' => 12, 'text' => '12 Hour'],
            ['value' => 24, 'text' => '1 Day'],
        ];

    $b = [
            ['value' => 12]
        ];
    $c = array();


    function checkExists($array,$value){
        foreach($array as $k=>$values){
            if($values['value']==$value){
                return true;break;
            }
        }
        return false;
    }
    foreach($a as $k=>$v){
        if(checkExists($b,$v['value'])===false){
            $c[$k]=$v;
        }
    }
?>

Output

Array
(
    [0] => Array
        (
            [value] => 1
            [text] => 1 Hour
        )

    [2] => Array
        (
            [value] => 24
            [text] => 1 Day
        )

)

answered Jul 1, 2017 at 10:57

Jaydeep Mor

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Comments

Terry · Accepted Answer · 2017-07-01 11:01:27Z

1

There's no need to author very complicated for loops. You can simply define your own comparator function when using array_udiff():

$a = [
        ['value' => 1, 'text' => '1 Hour'],
        ['value' => 12, 'text' => '12 Hour'],
        ['value' => 24, 'text' => '1 Day'],
    ];

$b = [
        ['value' => 12],    
    ];

function comparator($a, $b)
{
    return $a['value'] - $b['value'];
}

$c = array_udiff($a, $b, 'comparator');
print_r($c);

That should give you the array you expected:

Array (
    [0] => Array (
        [value] => 1
        [text] => 1 Hour
    )
    [2] => Array (
        [value] => 24
        [text] => 1 Day
    )
)

answered Jul 1, 2017 at 11:01

Terry

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Comments

bill.lee · Accepted Answer · 2017-07-01 11:09:59Z

Are you sure you didn't use array_diff()? You are misunderstanding array_diff_keys(); it only works with a single dimensional associative array—i.e., elements with keys. The first dimension of your array does not have any keys.

We can write a simple solution with array_reduce():

$a = [
        ['value' => 1, 'text' => '1 Hour'],
        ['value' => 12, 'text' => '12 Hour'],
        ['value' => 24, 'text' => '1 Day'],
    ];

$b = [
        ['value' => 12]
    ];

function filter($v1,$v2)
{
  global $b;
  var_dump($v1,$v2);
  return ($b[0]['value'] == $v2['value'])
    ? $v1
    : array_merge($v1, [$v2]);
}

print_r(array_reduce($a,"filter",[]));

Short, sweet, and no explicit iterators nor temporary variables.

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