I want to calculate the number of integers in the string "abajaao1grg100rgegege".
I tried using isnumeric() but it considers '100' as three different integers and shows the output 4. I want my program to consider 100 as a single integer.
Here is my attempt:
T = int(input())
for x in range(T):
S = input()
m = 0
for k in S:
if (k.isnumeric()):
m += 1
print(m)
I'd use a very basic regex (\d+) then count the number of matches:
import re
string = 'abajaao1grg100rgegege'
print(len(re.findall(r'(\d+)', string)))
# 2
You can use the regex library to solve this issue.
import re
st = "abajaao1grg100rgegege"
res = re.findall(r'\d+', st)
>>> ['1', '100']
You can check how many numbers you have on that list that the findall returned.
print (len(res))
>>> 2
In order to read more on python regex and the patterns, enter here
Regex is the go-to tool for this sort of problem, as the other answers have noted. However, here is a solution that uses looping constructs and no regex:
result = sum(y.isdigit() and not x.isdigit() for x,y in zip(myString[1:], myString))
In addition, here is an easy to understand, iterative solution, that also doesn't use regex and is much more clear than the other one, but also more verbose:
def getNumbers(string):
result = 0
for i in range(len(string)):
if string[i].isdigit() and (i==0 or not string[i-1].isdigit()):
result += 1
return result
Not very Pythonic but for beginners more understandable:
Loop over characters in string and in every iteration remember in the was_digit (logical variable) if the current character is digit - for the next iteration.
Increase the counter only if the previous character was not a digit:
string = 'abajaao1grg100rgegege'
counter = 0 # Reset the counter
was_digit = False # Was previous character a digit?
for ch in string:
if ch.isdigit():
if not was_digit: # previous character was not a digit ...
counter += 1 # ... so it is start of the new number - count it!
was_digit = True # for the next iteration
else:
was_digit = False # for the next iteration
print(counter) # Will print 2
random="1qq11q1qq121a21ws1ssq1";
counter=0
i=0
length=len(random)
while(i<length):
if (random[i].isnumeric()):
z=i+1
counter+=1
while(z<length):
if (random[z].isnumeric()):
z=z+1
continue
else:
break
i=z
else:
i+=1
print ("No of integers",counter)
