how to save output of a function to a variable in bash

Question

I have a function called fslnvols which gives the number of images in a 4D image.

Usage:

fslnvols <input>

I wanted to save the output of the function to variable A,so I tried:

A=fslnvols inputimage

and

fslnvols inputimage

A=$(fslnvols)

but I didn't get the wanted result, any idea how to fix it?

"but none of them worked" what does that mean? var=$(foo) will store the stdout of the foo command in $var. — dimo414
– dimo414, Commented Jul 3, 2017 at 4:55

heemayl · Accepted Answer · 2017-07-03 04:55:51Z

2

Use command substitution, $():

A=$(fslnvols inputimage)

The command whose output you want to store as variable A, goes inside $() -- fslnvols inputimage in this case.

answered Jul 3, 2017 at 4:55

heemayl

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