how to store form validation errors in an array

Question

If I have some basic form validations, (just using empty() for simplicities sake) and want to put those error messages into an array, how would I achieve this?

 $errors = array();
 $response = array();

if(empty($_POST['name'])) {

    $errors['name'] = "Name required";
}

if(empty($_POST['email'])) {

    $errors['email'] = "Email required";
}

$response['errors'] = $errors;

if(!empty($errors)) {

    $response['success'] = false;
    $response['message'] = "fail";

} else {

    $response['success'] = true;
    $response['message'] = "<div class='alert alert-success'>Success</div>";
}

echo json_encode($response);
}

I see you're using bootstrap. Are you using a PHP framework? — James
– James, Commented Jul 4, 2017 at 17:10
Just like Marvin said, use $message[] or $message = array(). then just iterate. — James
– James, Commented Jul 4, 2017 at 17:13
I actually need to update my code because I want to use json. But I still need to get the errors into an array. Please see new code — Iggy's Pop
– Iggy's Pop, Commented Jul 4, 2017 at 17:19

user10089632 · Accepted Answer · 2017-07-04 17:05:35Z

1

    $message = [];

if(empty($_POST['name'])) {

array_push($message , "Name required <br />");

}

if(empty($_POST['email'])) {

array_push($message , "Email required <br />");

}

if(!empty($message)) {
foreach ( $message as $str)
echo "<div class='alert alert-danger'>" . $str . "</div>";

} else {
// success 

}

answered Jul 4, 2017 at 17:05

user10089632

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1 Comment

Iggy's Pop Over a year ago

Apologies, I changed the code in the initial question

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