Using the sh Python module, avoid exception logging when killing a background process

Question

The following Python:

p=sh.sleep(100, _bg=True)

try:
  p.kill()
except sh.SignalException_SIGKILL:
  print('foo')

Gives me:

>>> Exception in thread background thread for pid 14892:
Traceback (most recent call last):

<blah blah blag, long stack trace elided> 

sh.SignalException_SIGKILL: 

RAN: /usr/bin/sleep 100

STDOUT:

STDERR:

How can I avoid the background thread logging an error for something I expect to happen?

Have you imported the logging module by any change? Also, have you looked at the docs? — cs95
– cs95, Commented Jul 5, 2017 at 22:07
No, I have not imported the logging module. Yes, I have looked at the docs. The code is from an example in the docs. — razeh
– razeh, Commented Jul 6, 2017 at 15:32

gbajson · Accepted Answer · 2018-12-28 12:33:42Z

4

In order to catch this exception execute your process with _bg_exec=False and execute p.wait().

In [21]: p = sh.sleep(100, _bg=True, _bg_exc=False)
    ...: try:
    ...:     p.kill()
    ...:     p.wait()
    ...: except sh.SignalException_SIGKILL as err:
    ...:     print("foo")
    ...:
foo

edited Dec 28, 2018 at 12:33

answered Dec 28, 2018 at 12:27

gbajson

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