How do I create a PHP array with 2 variables for each element without using an object?

Question

I'm new to PHP and would require some assistance if possible.

I have the array

array("Name" => $userName, "Age" => $userAge);

This works for one user but lets say I wanted to add multiple users that will all have a Name and Age how would I do that? Instead of passing is $userName would I have to pass it an array of user names and instead of $userage an array of user ages hence making it multidimesional?

Also for my purposes I cannot put the username and userage in an object and then simply add it to the array.

geoB · Accepted Answer · 2017-07-05 23:43:04Z

3

One way is:

array(
    array("Name" => $userName, "Age" => $userAge),
    array("Name" => $userName1, "Age" => $userAge1),
    array("Name" => $userName2, "Age" => $userAge2)
    ...
);

answered Jul 5, 2017 at 23:43

geoB

4,7287 gold badges45 silver badges75 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

A. J. Parr · Accepted Answer · 2017-07-06 00:38:25Z

Here is some sample code which should solve your problem given. The two input array, names and ages, do not need to be the same size, and the output array will insert default values ('N/A' for names, -1 for ages) where a corresponding name or age is missing.

$userNames = ['name1', 'name2', 'name3', 'name4'];
$userAges = [26,14,99];
$userNamesAndAges = [];

for ($i=0; $i < max(count($userNames), count($userAges)); $i++) {
    if (isset($userNames[$i])) {
        $userName = $userNames[$i]; 
    } else {
        $userName = 'N/A';
    }

    if (isset($userAges[$i])) {
        $userAge = $userAges[$i];
    } else {
        $userAge = -1;
    }

    $userNamesAndAges[] = [
        'Name' => $userName,
        'Age' => $userAge
    ];
}

foreach ($userNamesAndAges as $obj) {
    $name = $obj['Name'];
    $age = $obj['Age'];
    echo("Name: $name, Age: $age<br>"); 
}

Outputs:

Name: name1, Age: 26
Name: name2, Age: 14
Name: name3, Age: 99
Name: name4, Age: -1

Shuchi Sethi · Accepted Answer · 2017-07-05 23:46:29Z

1

Typecast the variables $userName and $userAge to array -

$userName = (array)$userName;
$userAge = (array)$userAge;

Iterate over them for further processing. It would then make no difference if the size of array was one or many.

answered Jul 5, 2017 at 23:46

Shuchi Sethi

8038 silver badges14 bronze badges

1 Comment

Barmar Over a year ago

How does this create an array of multiple users? It just makes an array of 1 user.

Collectives™ on Stack Overflow

How do I create a PHP array with 2 variables for each element without using an object?

3 Answers 3

Comments

Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related