parse data from Dictionary in python

Question

So i have this dictionary "runs":

[{
'id': 12,
'suite_id': 2,
'name': 'name',
'description': "desc.",
'nice_id': 3,
'joku_id': None,
'onko': False,
'eikai': False,
'tehty': None,
'config': None,
'config_ids': [],
'passed_count': 1,
'blocked_count': 2,
'untested_count': 3,
'retest_count': 4,
'failed_count': 5,
'custom_status1_count': 0,
'custom_status2_count': 0,
'custom_status3_count': 0,
'custom_status4_count': 0,
'custom_status5_count': 0,
'custom_status6_count': 0,
'custom_status7_count': 0,
'projekti_id': 1,
'plan_id': None,
'created_on': 12343214,
'created_by': 11,
'url': 'google.com'
}, {
'id': 16,
'suite_id': 2,
'name': 'namae)',
'description': "desc1",
'nice_id': 5,
'joku_id': None,
'onko': False,
'eikai': False,
'tehty': None,
'config': None,
'config_ids': [],
'passed_count': 100,
'blocked_count': 1,
'untested_count': 3,
'retest_count': 2,
'failed_count': 5,
'custom_status1_count': 0,
'custom_status2_count': 0,
'custom_status3_count': 0,
'custom_status4_count': 0,
'custom_status5_count': 0,
'custom_status6_count': 0,
'custom_status7_count': 0,
'prokti_id': 7,
'plan_id': None,
'created_on': 4321341644,
'created_by': 11,
'url': 'google.com/2' }

there is "id" for about 50 times. that is just a part of it. i need to find all "id":s (Not joku_ids, ncie_ids etc. Only "id") and make a string/dict of them and same for name, and description

i have tried:

j = json.load(run)
ids = (j["id"])

j = json.load(run)
names = (j["name"])

j = json.load(run)
descriptions = (j["description"])

but it returns:

AttributeError: 'list' object has no attribute 'read'

I also need to send a request with specific id and in this case the specific id is marked by o. so id[o] the request code is below:

test = client.send_get('get_tests/1/ ')

so i need to have the id[o] instead of the 1. i have tried

test = client.send_get('get_tests/' + id[o] + '/ ')

but it returns:

TypeError: 'int' object is not subscriptable

So you want id = [d['id'] for d in runs]

cs95
– cs95

2017-07-07 05:11:59 +00:00
Commented Jul 7, 2017 at 5:11 — cs95
– cs95, Commented Jul 7, 2017 at 5:11
what answer you expect, you want result in list or dict?

ammy
– ammy

2017-07-07 05:20:32 +00:00
Commented Jul 7, 2017 at 5:20 — ammy
– ammy, Commented Jul 7, 2017 at 5:20

Tejas Thakar · Accepted Answer · 2017-07-07 05:16:06Z

2

May be this can help you.

id = []
for i in runs :
    id.append(i.get('id'))

[12, 16]

answered Jul 7, 2017 at 5:16

Tejas Thakar

5835 silver badges19 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Tejas Thakar Over a year ago

It's my pleasure.

K. Kirsz · Accepted Answer · 2017-07-07 05:15:37Z

0

You are trying to pass a list to a json.load function. Please read the docs. Load() does not accep lists, it accepts

a .read()-supporting file-like object containing a JSON document

answered Jul 7, 2017 at 5:15

K. Kirsz

1,42011 silver badges12 bronze badges

Comments

ammy · Accepted Answer · 2017-07-07 05:43:40Z

0

If you want your result in list of dictionary then:

result = [{x:y} for i in range(len(data)) for x,y in data[i].items() if x=='id' or x=='name' or x=='description']

output:

[{'name': 'name'}, {'id': 12}, {'description': 'desc.'}, {'name': 'namae)'}, {'id': 16}, {'description': 'desc1'}]

the data is your list of dictionary data. hope this answer helpful for you.

edited Jul 7, 2017 at 5:43

answered Jul 7, 2017 at 5:33

ammy

6481 gold badge5 silver badges13 bronze badges

3 Comments

user8231578 Over a year ago

this works aswell but going with the. Tejas's answer. Thanks

user8231578 Over a year ago

Sorry. Forgot :). My code is so close to being done, but i have problem with my string that gets information. it should be like ('get_tests/1/ ') and i need to have a id[o] instead of the 1. i have tried ('get_tests/' + id[o] + '/ ') but it doens't work

ammy Over a year ago

i didn't get complete exactly what you want please mention properly or make changes in your question please.

Collectives™ on Stack Overflow

parse data from Dictionary in python

3 Answers 3

1 Comment

Comments

3 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

1 Comment

Comments

3 Comments

Your Answer

Sign up or log in

Post as a guest

Related