Parsing XML file in python

Question

    import requests
    import xml.etree.ElementTree as ET


    def abc(area_code, office_code): 
        args = area_code + office_code
     url = (described bellow)
     r = requests.get(url=url)
     tree=ET.ElementTree()
     parsed_data=tree.parse(r.content)
      return parsed_data

   abc('503', '402')

where url is

url="http://www.networksolutions.ds.adp.com/NSPhoneToolDB/template/GetBusRouteFilterExpressions.xml?"\
               "Telnum=" +args+ "&FilterNamePrefix=ORPORTCDK&ReturnResult=detail"

when i run this thing i am getting

<Element 'GetBusRouteFilterExpressions' at 0x7f2abf526f48>

as output instead of entire file.

Bharel · Accepted Answer · 2017-07-07 20:32:54Z

1

You're giving it the response object itself.

Try giving it the content of the response like so parsed_data=tree.parse(r.content).

answered Jul 7, 2017 at 20:32

Bharel

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2 Comments

shashank Over a year ago

yes it worked but now it just prints <Element 'GetBusRouteFilterExpressions' at 0x7f952bfc3f48>

Bharel Over a year ago

And what's the problem

David · Accepted Answer · 2017-07-07 20:34:36Z

1

When you make the request in python you're getting back a response object. You need to parse the body of that response instead. So

tree.parse(r.content)

answered Jul 7, 2017 at 20:34

David

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Comments

stovfl · Accepted Answer · 2017-07-08 16:56:10Z

0

Read and try the example from

The ElementTree XML API: 20.5.1.2. Parsing XML

As an Element, root has a tag and a dictionary of attributes:
    \>>> root.tag
    'data'
    \>>> root.attrib
    {}
It also has children nodes over which we can iterate:
    \>>> for child in root:
    ...     print(child.tag, child.attrib)
    ...
    country {'name': 'Liechtenstein'}
    country {'name': 'Singapore'}
    country {'name': 'Panama'}
Children are nested, and we can access specific child nodes by index:
   \ >>> root[0][1].text
    '2008'

answered Jul 8, 2017 at 16:56

stovfl

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