PHP function to remove key from a query string

Question

I have a query string, like:

n1=v1&n2=v2&n3=v3

etc

I just want a php function that will accept the query string and the name (key), and remove the name value pair from the querystring.

Every example I have found uses regexes and assumes that the value will exist and that it will not be empty, but in my case (and possibly in general, I would like to know) this would also be a valid query:

n1=v1&n2=&n3

I don’t know in advance how many keys there will be.

I am convinced that regexes are monsters that eat time. Eventually all matter in the universe will end up in a regex.

I'm upping it for the regexes eat time comment... far too few people see that they are usually NOT the right tool for the job. — Shark8
– Shark8, Commented May 3, 2012 at 1:21

ajreal · Accepted Answer · 2010-12-22 06:30:46Z

12

parse_str('n1=v1&n2=&n3', $gets);
unset($gets['n3']);
echo http_build_query($gets);

NOTE: unset($gets['n3']); is just a show-case example

edited Dec 22, 2010 at 6:30

answered Dec 21, 2010 at 10:58

ajreal

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7 Comments

Not Available Over a year ago

Exactly what I would have suggested

zod Over a year ago

@Alexander.Plutov I can't see anything wrong with this. It seems to work for me.

zod Over a year ago

@symcbean I did not mean to suggest the answer had to have something to do with regexes, it is just that the answers I found on the web all used regexes and preg_replace. I much prefer the answers that don't.

ajreal Over a year ago

@zod - don't worry, I guess he having mis-understanding on the question, no worry -2 only...

Alex Pliutau Over a year ago

@zod. Yuo wrote remove the name value pair from the querystring. This code removes only value. n1=v1&n2=.

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Oli · Accepted Answer · 2010-12-21 10:57:27Z

0

function stripkey($input, $key) {

$parts= explode("&", $input);

foreach($parts as $k=>$part) {

    if(strpos($part, "=") !== false) {
        $parts2= explode("=", $part);

        if($key == $parts2[0]){

            unset($parts[$k]);
        }
    } 
}
return join("&", $parts);

}

answered Dec 21, 2010 at 10:57

Oli

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