How to Set Image as a Variable in Php and display the image in HTML using that variable

Question

So i have a query running and i get results in a while loop. In the while loop I want to set $image as a variable for a image that is needed to be displayed on a html page, by using the variable. I am not able to get the image displayed on the html.

By the way the images are located in the folder.

PHP Code :

    if ($result->num_rows > 0) {

while($row = $result->fetch_assoc()) {
          $image = "<img src='images/image1.png'>";
    }
}

HTML Code:

<?php include 'File.php';?>
 <img src="<?php echo $image; ?>" alt="Mountain View" style="width:304px;height:228px;">

Djordje Vujicic · Accepted Answer · 2017-07-14 19:43:16Z

1

Just change $image = "<img src='images/image1.png'>"; to $image = "images/image1.png"; and then do:

echo '<img src="' . $image . '"/>';

or in your case

<img src="<?php echo $image; ?>" alt="Mountain View" style="width:304px;height:228px;"/>

answered Jul 14, 2017 at 19:43

Djordje Vujicic

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