My Date = 2015-07-30
2015-07-31
2015-08-03
2015-08-04
2015-08-05
2015-08-06
2015-08-07
2015-08-10
2015-08-11
2015-08-12
2015-08-13
2015-08-14
How can I call every 2nd date from here? I tried this but this doesn't work.
for i in range(0, len(Date), 2):
abc = Date[i]
You can write this to get every other date (index 0, 2, 4, ...) from your list:
Date[::2]
To get the other dates (index 1, 3, ...), you can write:
Date[1::2]
You can look at this answer for an explanation of the slice notation.
Since Date is a list, you might want to call it dates in order to indicate it's a collection:
dates = """2015-07-30
2015-07-31
2015-08-03
2015-08-04
2015-08-05
2015-08-06
2015-08-07
2015-08-10
2015-08-11
2015-08-12
2015-08-13
2015-08-14""".split()
print(dates[::2])
# ['2015-07-30', '2015-08-03', '2015-08-05', '2015-08-07', '2015-08-11', '2015-08-13']
print(dates[1::2])
# ['2015-07-31', '2015-08-04', '2015-08-06', '2015-08-10', '2015-08-12', '2015-08-14']
my_dates = ['2015-07-30', '2015-07-31', '2015-08-03', '2015-08-04', '2015-08-05', '2015-08-06', '2015-08-07', '2015-08-10', '2015-08-11', '2015-08-12', '2015-08-13', '2015-08-14']
Using list comprehension:
print([my_dates[i] for i in range(1, len(my_dates), 2)])
Output:
['2015-07-31', '2015-08-04', '2015-08-06', '2015-08-10', '2015-08-12', '2015-08-14']
For above sample code, you can replace start index as 1 and observe by printing:
for i in range(1, len(my_dates), 2):
abc = my_dates[i]
print(abc)
Happy Coding.
MyDate? A list? Furthermore what you you mean with "call"? What is the expected output?