create dynamic tree using php

Question

I have a code for dynamic tree view using php mysql.

function fetchCategoryTreeList($parent = '', $user_tree_array = '') 
{
  // code here 
}

i just want ...like. i have a variable

$top = '1234';

now how to put in this function like

function fetchCategoryTreeList($parent = $top, $user_tree_array = '') 
{
  // code here 
}

if i put $top in this function then i got fatal error. Please help me

Can't have a fatal error just by adding $top = '1234' ; into the function. We need your real code to see the problem. — Pierre Granger
– Pierre Granger, Commented Jul 22, 2017 at 10:09
@PierreGranger He got error because of $parent = $top in function argument — B. Desai
– B. Desai, Commented Jul 22, 2017 at 10:11
Oops sorry that was obvious. Op, why you want to do that ? $parent='' in function declaration is just a "default" value, most of the time you don't have to set one. Il you really need : function foo($var,$var2) { global $top ; if ( $var == null ) $var = $top ; ... } — Pierre Granger
– Pierre Granger, Commented Jul 22, 2017 at 10:13

B. Desai · Accepted Answer · 2017-07-22 10:14:34Z

1

You cant assign default value as another variable to arguments. You can use constant instead

define("TOP", "1234");
function fetchCategoryTreeList($parent = TOP, $user_tree_array = '') 
{
  // code here 
}

answered Jul 22, 2017 at 10:14

B. Desai

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Comments

Pierre Granger · Accepted Answer · 2017-07-22 10:15:27Z

0

If you really need a default dynamic value :

$top = '1234' ;

// Some code

function fetchCategoryTreeList($parent = '', $user_tree_array = '') 
{
  global $top ;
  if ( $parent == null || $parent == '' ) $parent = $top ;
  // code here 
}

But if the value is constant take a look at B Desai answer.

answered Jul 22, 2017 at 10:15

Pierre Granger

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