Java using regex to replace At position 4, 5 and 6 words from a string [duplicate]

Question

Can i use a regex to replace the 4th, 5th, 6th words with * from a string ?

Actually i do this:

public class Test
{
    public static void main( String[] args )
    {
        StringBuilder myName = new StringBuilder("AD-BJR5U");
        myName.setCharAt(3, '*');
        myName.setCharAt(4, '*');
        myName.setCharAt(5, '*');
        System.out.println(myName);
    }
}

Input:

AD-BJR5U

Output:

AD-***5U

Much more clearer and human-understandable. I don't think the same. — revo
– revo, Commented Jul 25, 2017 at 8:33
If you want to improve your code then you have to extract this functionality into method or just use builder.replace(3, 6, "***"); — Flown
– Flown, Commented Jul 25, 2017 at 8:38

revo · Accepted Answer · 2017-07-25 08:45:46Z

4

Your current approach is very clear and straight forward I'd go with that if I were you. Anyway Regular Expressions are an option:

(?<=^(?:.{3}|.{4}|.{5})).

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edited Jul 25, 2017 at 8:45

answered Jul 25, 2017 at 8:38

revo

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NatNgs · Accepted Answer · 2017-07-25 08:39:36Z

3

Following the example you give, I will answer something like that:

// Keeping 3 firsts char; will replace the 3 of the center, and keep all to the end
^(.{3}).{3}(.*)$

So in Java:

str.replaceAll("^(.{3}).{3}(.*)$", "$1***$2");

answered Jul 25, 2017 at 8:39

NatNgs

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Viet · Accepted Answer · 2017-07-25 08:39:34Z

2

You can try with replace(int start, int end, String str) method of StringBuilder

myName.replace(3, 6, "***");

answered Jul 25, 2017 at 8:39

Viet

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