Python TypeError: object() takes no parameters error

Question

I'm a beginner in Python. I'm following "Learn Python In The Hard Way". In Exercise 40, I tried to write a short code but got an error. Please help me :(

Source

class showInfo(object):
    'Initialize a classL'
    def __int__(self, name, phone, age):
        self.name = name
        self.phone = phone
        self.age = age

def showName(self):
    print("Name: "+self.name)
def showAge(self):
    print("Age: "+self.age)
def showPhone(self):
    print("Phone: "+self.phone)

emp1 = showInfo("JJJ")

emp1.showName()

Debug

Traceback (most recent call last):
File "classes.py", line 15, in <module>
    emp1 = showInfo("JJJ")
TypeError: object() takes no parameters

Raymond Hettinger · Accepted Answer · 2017-07-26 00:52:07Z

9

The cause is that __init__ is misspelled :-)

After that, there will be a different error message because showInfo("JJJ") only passes in one parameter when three are needed showInfo(somename, somephone, someage).

After that, there will be yet one more message because the last three methods are not properly indented under the class definition.

Here is the fixed-up code:

class showInfo(object):
    'Initialize a classL'
    def __init__(self, name, phone, age):
        self.name = name
        self.phone = phone
        self.age = age

    def showName(self):
        print("Name: "+self.name)

    def showAge(self):
        print("Age: "+self.age)

    def showPhone(self):
        print("Phone: "+self.phone)

emp1 = showInfo("Tom", "555-1212", 21)
emp1.showName()

This outputs:

Name: Tom

edited Jul 26, 2017 at 0:52

answered Jul 26, 2017 at 0:49

Raymond Hettinger

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1 Comment

Raj Subit Over a year ago

Also, titlecase should be used for defining classname. class ShowInfo(object).

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