AttributeError: 'NoneType' object has no attribute 'encode' in python 2.7

Question

for item in root.findall('./channel/item'):
    news = {}
    # iterate child elements of item
    for child in item:
        # special checking for namespace object content:media
        if child.tag == '{http://search.yahoo.com/mrss/}content':
            news['media'] = child.attrib['url']
        else:
            news[child.tag] = child.text.encode('utf8')
    newsitems.append(news)

whats the problem ?? how am i gonna solve this problem?

that's because child.text is None. Filter it out. if child.text: ... — Jean-François Fabre
– Jean-François Fabre ♦, Commented Jul 26, 2017 at 9:05

Jean-François Fabre · Accepted Answer · 2017-07-26 09:08:22Z

3

here:

    else:
        news[child.tag] = child.text.encode('utf8')

child.text is None in some cases. So don't create the dict entry in that case, for instance like this:

    elif child.text is not None:
        news[child.tag] = child.text.encode('utf8')

answered Jul 26, 2017 at 9:08

Jean-François Fabre♦

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