I have an nested array unsorted after sorting it should be sorted depending on 2nd item of sub-array
var unsorted = [["tag_17",0,4],["tag_18",13,18],["tag_435",6,11]];
var sorted = [["tag_18",13,18], ["tag_435",6,11], ["tag_17",0,4]];
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2btw, you have a nested array.Nina Scholz– Nina Scholz2017-07-27 06:23:58 +00:00Commented Jul 27, 2017 at 6:23
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Sorry, Wrong choice of words :(Abdullah Ahmed– Abdullah Ahmed2017-07-27 06:30:00 +00:00Commented Jul 27, 2017 at 6:30
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2 Answers
var a = [
["tag_17", 0, 4],
["tag_18", 13, 18],
["tag_435", 6, 11]
];
a.sort(sortFunction);
console.log(a);
function sortFunction(a, b) {
if (a[0] === b[0]) {
return 0;
}
return (a[1] < b[1]) ? 1 : -1;
}You can read the documentation about sort.
4 Comments
Abdullah Ahmed
Thanks buddy. It worked...
Milan Chheda
You're welcome. Up-vote and mark it as close. Happy Coding!!! :)
Abdullah Ahmed
Found a working answer here too stackoverflow.com/a/12788202/2597670
Milan Chheda
Yes, just Google or StackOverflow and could have found multiple answers as
sort is straight-forward and easy to use.var unsorted = [["tag_17",0,4],["tag_18",13,18],["tag_435",6,11]];
sorted = unsorted.sort((a,b) => {
return b[1] - a[1];
} )
console.log(sorted);
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