Javascript: Sort array of arrays by second element in each inner array

Question

I have an array that looks like this:

const arr = [
  [500, 'Foo'],
  [600, 'bar'],
  [700, 'Baz'],
];

I would like to sort this arr alphabetically by the second element in each inner array, ie:

[
  [600, 'bar'],
  [700, 'Baz'],
  [500, 'Foo'],
]

Note the case insensitivity. Also, I would love to use lodash helpers if they come in handy here!

Array.prototype.sort, no lodash or anything else is required. — zerkms
– zerkms, Commented Sep 19, 2016 at 23:02
Read the docs, specifically the stuff about a custom compare function. — qxz
– qxz, Commented Sep 19, 2016 at 23:05

qxz · Accepted Answer · 2016-09-19 23:24:26Z

10

Here is a concrete, working example, using Array.prototype.sort:

const arr = [
  [500, 'Foo'],
  [600, 'bar'],
  [700, 'Baz']
];

arr.sort((a,b) => a[1].toUpperCase().localeCompare(b[1].toUpperCase()));

console.log(arr);

answered Sep 19, 2016 at 23:24

qxz

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Comments

jlogan · Accepted Answer · 2016-09-19 23:10:44Z

2

Array.prototype.sort takes a function which will be applied to each pair of items in the array. The return of that function determines how the items are sorted (it needs to return a positive number, 0, or a negative number).

edited Sep 19, 2016 at 23:10

answered Sep 19, 2016 at 23:05

jlogan

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