Supose this code
a = pd.DataFrame([1,2,3])
if I do
a.loc[0,'A']=3
I get:
0 A
0 1 3
1 2 NaN
2 3 NaN
Now suppose that:
a = pd.DataFrame([1,2,3])
b=pd.DataFrame([[5,4],[6,3],[7,2]],columns=['B','C'])
Is there a way to do a[1,'A','B']=b[2] that gets as result
0 B C
0 1 NaN NaN
1 2 7 2
2 3 NaN NaN
Update: I have change a bit the question because the answers supose that a and b have same indexes and it is not.
You could use join on a with required row of b
In [150]: a.join(b.loc[0:0])
Out[150]:
0 B C
0 1 5.0 4.0
1 2 NaN NaN
2 3 NaN NaN
One possibility:
import pandas as pd
a = pd.DataFrame([1, 2, 3])
b = pd.DataFrame([[5, 4], [6, 3], [7, 2]], columns=['B', 'C'])
a.loc[0, 'B'] = b.loc[0, 'B']
a.loc[0, 'C'] = b.loc[0, 'C']
which gives as a:
0 B C
0 1 5.0 4.0
1 2 NaN NaN
2 3 NaN NaN
How about pd.concat:
pd.concat([a,b.loc[b.index==0,:]],axis=1)
Out[53]:
0 B C
0 1 5.0 4.0
1 2 NaN NaN
2 3 NaN NaN
